Question

No. of atoms in 19.7g of Gold is?

Answer 1

@Abhisar

Answer 2

Ok, first you need to calculate the no. of moles of gold in 19.7g of gold. Do you know how to do that?

Answer 3

\(\sf No.~of~moles=\huge \frac{Give~mass}{Atomic~mass}\)

Answer 4

Shouldn't it be atomic mass/given mass?

Answer 5

No. Given mass/Atomic Mass

Answer 6

so,thats 0.1 mole?

Answer 7

Yes, now multiply this by Avogadro's constant to get the number of atoms. Because one mole of anything has no of atoms equivalent to Avogadro's constant

Answer 8

6.022 into 10^23

Answer 9

Yes, that's avogadro's constant

Answer 10

The answer would be \(\sf 0.1 \times N_A\)

Answer 11

\(\sf N_A\)= Avogadro's Constant

Answer 12

so is it 6.022*10^22?

Answer 13

Yes, now do you understand how to do this?

Answer 14

Yes.

Answer 15

OK, cool