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OpenStudy (michaeljordan23):

describe why circular permutations are different from linear permutaions

OpenStudy (mjdennis):

A linear permutationis the usual kind; 1-2-3, 1-3-2, 2-3-1, 2-1-3, 3-1-2, 3-2-1. Can you describe what a circular permutation is?

OpenStudy (michaeljordan23):

it's the number of ways to arrange distinct objects along a fixed circle is

OpenStudy (mjdennis):

So let's take a linear permutation of 4 items. How many (linear) permutations are there (as an expression, don't multiply it out yet)

OpenStudy (mjdennis):

Let's look at the first permutation: 1-2-3-4:|dw:1464630233979:dw| There are four _identical_ circular permutations for this one linear permutation, right?

OpenStudy (michaeljordan23):

yes, so what is the difference between the two?

OpenStudy (mjdennis):

Well, not to be a smart alec,but that's the part you are supposed to be figuring out, isn't it? Take the formula for linear permutation. Note that if you have X linear permutations for n positions, you have _fewer_ circular permutations, because there are n identical linear permutations of each circular permutation. There are X/n circular permutations. Figure what X is, plug it in. HINT: I say you solve 'the same' problem that this reduces to, about 20 minutes ago with @mathstudent55 You can figure this out.

OpenStudy (michaeljordan23):

okay thank you

OpenStudy (mjdennis):

Sorry, I misread the question, to describe why. Did you figure out why? If you join the ends of a linear into a circle, what happens? Can you explain why 1/n permutations are now identical?

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