#6/7. Math/Geometry. *Picture attached in question.*
you need help with questions 6 and 7?
yeah
do you have a calculator or trigonometric tables or something?
@baru Yes I have a calculator ... what are trig tables?
Trig tables are printed trigonometric values usually found in a trigonometry book. sin 1 degree = .0175 sin 2 degrees = .034899
Since you have a calculator, you don't need them.
Were you going to ask a question?
So what do I plug in ...or how to i complete the problem ... whats the layout of the steps? @wolf1728
In trigonometry if you know one angle and one side of a right triangle you can solve for all the other sides and angles. Looking at fiure 6, we have one side but we need to know an angle. Let's suppose the angle in the upper left corner of the triangle is angle A. What does angle A measure?
20?
Well, I meant the angle nest to that I'll redraw that graphic. Why do they label graphics so rotten?
Angle A plus angle 20 degrees form a right angle. (90 degrees) Since we already know the 20 degree angle, what does angle A equal?
Angle A plus 20 degrees = 90 degrees What does Angle A equal?
Gee, is anybody else still "playing" this game?
yeah
sorry i got a call @wolf1728
70? @wolf1728
yes, 70 now do you know the definition of 'cosine' of an angle? or cos(A)
The length of the adjacent side divided by the length of the hypotenuse. @baru
can you recognize which side is adjacent and which side is the hypotenuse with respect to the angle you just found?
h=x, a= bottom, opp.=300m @baru
|dw:1464713584905:dw|
can you look at that and try again?
@CoExist2 are you there??
h=x, a=300, opp.= blank. @baru
@baru @wolf1728 Is it something like this for number 6.? 70+20=90... negative 1/2 (one half.)...102.606043...Cos (70)/1=300/x... cross ~ bowtie...300/.342=.342x/.342...x=877.19=880. ??
We know angle A is 70 degrees The cosine of 70 degrees = adjacent / hypotenuse the hypotenuse (or "x") = adjacent / cos (70) hypotenuse = 300 / .34202 hypotenuse =877.142 It seems you were REALLY close with your answer of 877.19 The only difference was that I looked up a more accurate value of cosine of 70 degrees. The fact is you got it right!!
i need some help
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