I did a few of these questions before hand, and now all of a sudden I'm stuck. I have to find which equation is shown on the graph below and I'm confused because the lines seem to go IN BETWEEN the numbers and I don't know which way to represent it. See graph below.
|dw:1464701805827:dw|
The graph shows increase because it goes up left to right so you already know you'll be adding or multiplying
I more inclined to think that I'll be adding.
I would look for points where it's easy to read off an (x,y) point on the line for example, (0, -4) and (2,0)
the "number labels" are for the "lines", and you know you start at x=0 (for example) and the "1" goes with the next line over from x=0
|dw:1464702140094:dw| Those two pts are clearest. So you can find the gradient from these pts, then sub one of the pts and this gradient into y - y1 = m(x - x1) to find the equation. Alternatively, the two pts are also your x and y intercepts, and the equation of any line with x intercept of A and y intercept of B is given by: \[\frac{ x }{ A }+\frac{ y }{ B } =1\]
once you have two points, you can find the slope, and then the equation or you could count: up 4 and over 2 (starting at (0,-4) and going to (2,0) ) that makes the slope (i.e. change in y is up divided by change in x (over) ) 4/2 or 2
Agh! A tad confused with all these variable's of y and slope and points....so I'm just re-reading everything that was written over again.
Okay, so does 2x + y make any sense as an equation for this? @phi @mww
I would stick with the formula y = mx + b you know m is 2 (that is the slope) you now need "b", the y-intercept
Well, at the moment I'm stuck with Ax + By = C standard formula. That is what the whole assignment I'm working on is based off of. Thats specifically what they are trying to teach me.
@Atsie are they asking you to write the equation in general form?
Well, if general form is the way to put it then I suppose so. y = mx + b has never been mentioned yet.
oh. I guess there might be quick ways to write an equation in standard form, but I would write it in slope intercept form, then translate to standard form.
mww shows how to use the "intercepts" to write the equation in the form \[ \frac{x}{x-intercept} + \frac{y}{y-intercept} = 1\] and we can read off the intercepts, so that is easy to write down. then we "clear the denominators" to make it standard form. (if that makes sense??)
so, in this special case, where we know both intercepts, we can use the formula \[ yintercept \cdot x + xintercept \cdot y = xintercept \cdot yintercept \]
you would still want to simplify by factoring out any common multiple.
another way to tackle this is use the idea of ratios, for a line that goes through (0,0) \[ \frac{y}{x} = m \] in this case: \[ \frac{y}{x} = 2 \\ y = 2x\\ 0= 2x - y\\ 2x-y=0\] then put in a point e.g. (2,0) to get 2*2-0 = 4 to find the right hand side. you get 2x-y= 4
@phi Eee! Okay, I'm going to ignore the ratio and intercept thing right now because its absolutely overwhelming and to much information for me to understand. Do you know of a way though, to do this simply by standard form only? Or have you yourself not really become accustomed to SF ?
Also, I don't have 2x - y = 4 as an option for this question....so I'm extra confused.
I assume that your lesson explains how they want you to do this problem. I'm guessing it's a very specific approach ?
standard form usually means: variables in alphabetical order (so x before y) and usually, the leading coefficient is make positive. but you could write it as -2x+y= -4
can you describe (or post) how they expect you to do this problem ?
Well, I don't know how specifically to describe it but I'll try. They basically want me doing everything via standard form. They describe standard form as obviously stated Ax + By = C and then they also say that where \[A \ge 0\] , A and B are not both zero, and A, B, and C are integers with a greatest common factor of 1. This also ties into the fact that I'm learning about linear equations and functions. Is that of any help? @phi I mean basically, they expect me to do it in standard form somehow.
ok, that is what I understand as "standard form" But, do they give an example of how to translate info on a graph into standard form?
Hmm, let me go look. Sorry, I should actually have the book open and I'm being a total dunce :P
The only info I'm given really is that the x coordinate of a point at which the graph of an equation crosses the x - axis is called a x-intercept and the y coordinate of the point at which the graph crosses the y axis is called a y intercept. Then I'm also told that the values of x for something in the case of \[F(x) = 0\] are called zero's of the function f. So the zero of a function is its x intercept. Thats all there is.
ok. what grade is this? what course ?
9th grade Algebra I (don't judge. :P I'm actually supposed to be going into 11th grade math soon but as you can see I'm not great at it)
ok, and do they have an example where they show a graph of a line and explain how to find the equation of the line ?
They literally do not. I've looked all over the place.
can you post a snapshot of the first page of the chapter or section that has this question ?
I am thinking that you learn one way to do this, but I would rather it was in the book. But *everybody* learns about slope of a line and that is one way to do this problem, so we could learn that.
Alright, here lets go with this. I am told to read page 173 and thats it. https://www.mpaper.net/mpaper.php?hash=84a30c61-460c-4394-b11c-c57fdb25a780 Unless there is something else that I'm supposed to read and didn't or unless there is something that I missed...who knows maybe you could find something.
From what I see, they want you to "read off" the x-intercept and the y-intercept from the graph. can you do that for this problem ?
Well I can try, but I don't necessarily understand how.
do you know which line is the "x-axis" ? it's the thick horizontal (sideways) line labeled with numbers.
Yes, I do :)
find where the line crosses the x-axis. (mww shows in a post up above) the "x-intercept" is how far sideways you are on the x-axis away from the "origin"
any idea what the x-value is of the "x-intercept" ?
Its two, isn't it?
yes. and in case it's not obvious, the y-value is 0 (you are not above or below ) so that point has (x,y) numbers of (2,0)
next, what is the "y-intercept" (where the line crosses the vertical y-axis)
Well the y-intercept kind of gets me, because it runs straight into -5 but yet is on -4 at the same time.
ok, but we only care about the "lines" the labels are there for convenience (otherwise you would have to count, starting from the origin)
For example |dw:1464707314455:dw|
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