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Mathematics 15 Online
Atsie (atsie):

I did a few of these questions before hand, and now all of a sudden I'm stuck. I have to find which equation is shown on the graph below and I'm confused because the lines seem to go IN BETWEEN the numbers and I don't know which way to represent it. See graph below.

Atsie (atsie):

|dw:1464701805827:dw|

OpenStudy (xsniperxtreme):

The graph shows increase because it goes up left to right so you already know you'll be adding or multiplying

Atsie (atsie):

I more inclined to think that I'll be adding.

OpenStudy (phi):

I would look for points where it's easy to read off an (x,y) point on the line for example, (0, -4) and (2,0)

OpenStudy (phi):

the "number labels" are for the "lines", and you know you start at x=0 (for example) and the "1" goes with the next line over from x=0

OpenStudy (mww):

|dw:1464702140094:dw| Those two pts are clearest. So you can find the gradient from these pts, then sub one of the pts and this gradient into y - y1 = m(x - x1) to find the equation. Alternatively, the two pts are also your x and y intercepts, and the equation of any line with x intercept of A and y intercept of B is given by: \[\frac{ x }{ A }+\frac{ y }{ B } =1\]

OpenStudy (phi):

once you have two points, you can find the slope, and then the equation or you could count: up 4 and over 2 (starting at (0,-4) and going to (2,0) ) that makes the slope (i.e. change in y is up divided by change in x (over) ) 4/2 or 2

Atsie (atsie):

Agh! A tad confused with all these variable's of y and slope and points....so I'm just re-reading everything that was written over again.

Atsie (atsie):

Okay, so does 2x + y make any sense as an equation for this? @phi @mww

OpenStudy (phi):

I would stick with the formula y = mx + b you know m is 2 (that is the slope) you now need "b", the y-intercept

Atsie (atsie):

Well, at the moment I'm stuck with Ax + By = C standard formula. That is what the whole assignment I'm working on is based off of. Thats specifically what they are trying to teach me.

OpenStudy (mww):

@Atsie are they asking you to write the equation in general form?

Atsie (atsie):

Well, if general form is the way to put it then I suppose so. y = mx + b has never been mentioned yet.

OpenStudy (phi):

oh. I guess there might be quick ways to write an equation in standard form, but I would write it in slope intercept form, then translate to standard form.

OpenStudy (phi):

mww shows how to use the "intercepts" to write the equation in the form \[ \frac{x}{x-intercept} + \frac{y}{y-intercept} = 1\] and we can read off the intercepts, so that is easy to write down. then we "clear the denominators" to make it standard form. (if that makes sense??)

OpenStudy (phi):

so, in this special case, where we know both intercepts, we can use the formula \[ yintercept \cdot x + xintercept \cdot y = xintercept \cdot yintercept \]

OpenStudy (phi):

you would still want to simplify by factoring out any common multiple.

OpenStudy (phi):

another way to tackle this is use the idea of ratios, for a line that goes through (0,0) \[ \frac{y}{x} = m \] in this case: \[ \frac{y}{x} = 2 \\ y = 2x\\ 0= 2x - y\\ 2x-y=0\] then put in a point e.g. (2,0) to get 2*2-0 = 4 to find the right hand side. you get 2x-y= 4

Atsie (atsie):

@phi Eee! Okay, I'm going to ignore the ratio and intercept thing right now because its absolutely overwhelming and to much information for me to understand. Do you know of a way though, to do this simply by standard form only? Or have you yourself not really become accustomed to SF ?

Atsie (atsie):

Also, I don't have 2x - y = 4 as an option for this question....so I'm extra confused.

OpenStudy (phi):

I assume that your lesson explains how they want you to do this problem. I'm guessing it's a very specific approach ?

OpenStudy (phi):

standard form usually means: variables in alphabetical order (so x before y) and usually, the leading coefficient is make positive. but you could write it as -2x+y= -4

OpenStudy (phi):

can you describe (or post) how they expect you to do this problem ?

Atsie (atsie):

Well, I don't know how specifically to describe it but I'll try. They basically want me doing everything via standard form. They describe standard form as obviously stated Ax + By = C and then they also say that where \[A \ge 0\] , A and B are not both zero, and A, B, and C are integers with a greatest common factor of 1. This also ties into the fact that I'm learning about linear equations and functions. Is that of any help? @phi I mean basically, they expect me to do it in standard form somehow.

OpenStudy (phi):

ok, that is what I understand as "standard form" But, do they give an example of how to translate info on a graph into standard form?

Atsie (atsie):

Hmm, let me go look. Sorry, I should actually have the book open and I'm being a total dunce :P

Atsie (atsie):

The only info I'm given really is that the x coordinate of a point at which the graph of an equation crosses the x - axis is called a x-intercept and the y coordinate of the point at which the graph crosses the y axis is called a y intercept. Then I'm also told that the values of x for something in the case of \[F(x) = 0\] are called zero's of the function f. So the zero of a function is its x intercept. Thats all there is.

OpenStudy (phi):

ok. what grade is this? what course ?

Atsie (atsie):

9th grade Algebra I (don't judge. :P I'm actually supposed to be going into 11th grade math soon but as you can see I'm not great at it)

OpenStudy (phi):

ok, and do they have an example where they show a graph of a line and explain how to find the equation of the line ?

Atsie (atsie):

They literally do not. I've looked all over the place.

OpenStudy (phi):

can you post a snapshot of the first page of the chapter or section that has this question ?

OpenStudy (phi):

I am thinking that you learn one way to do this, but I would rather it was in the book. But *everybody* learns about slope of a line and that is one way to do this problem, so we could learn that.

Atsie (atsie):

Alright, here lets go with this. I am told to read page 173 and thats it. https://www.mpaper.net/mpaper.php?hash=84a30c61-460c-4394-b11c-c57fdb25a780 Unless there is something else that I'm supposed to read and didn't or unless there is something that I missed...who knows maybe you could find something.

OpenStudy (phi):

From what I see, they want you to "read off" the x-intercept and the y-intercept from the graph. can you do that for this problem ?

Atsie (atsie):

Well I can try, but I don't necessarily understand how.

OpenStudy (phi):

do you know which line is the "x-axis" ? it's the thick horizontal (sideways) line labeled with numbers.

Atsie (atsie):

Yes, I do :)

OpenStudy (phi):

find where the line crosses the x-axis. (mww shows in a post up above) the "x-intercept" is how far sideways you are on the x-axis away from the "origin"

OpenStudy (phi):

any idea what the x-value is of the "x-intercept" ?

Atsie (atsie):

Its two, isn't it?

OpenStudy (phi):

yes. and in case it's not obvious, the y-value is 0 (you are not above or below ) so that point has (x,y) numbers of (2,0)

OpenStudy (phi):

next, what is the "y-intercept" (where the line crosses the vertical y-axis)

Atsie (atsie):

Well the y-intercept kind of gets me, because it runs straight into -5 but yet is on -4 at the same time.

OpenStudy (phi):

ok, but we only care about the "lines" the labels are there for convenience (otherwise you would have to count, starting from the origin)

OpenStudy (phi):

For example |dw:1464707314455:dw|

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