Question

HELP

Answer 1

Sorry, I have to get back to work. @phi might be a good help.
The previous help was here: http://openstudy.com/study#/updates/574d8dbee4b056c4b3e5d9b5
Good luck!

Answer 2

You got that the period of \(f(\theta)\) is half the period of \(g(\theta)\).
Since \(g(\theta)\) has a period of \(2\pi\), \(f(\theta)\) has a period of \(4\pi\).
So \[f(\theta)=a \sin(\frac{ \theta }{ 2 })\]

Answer 3

\[f(\frac{\pi}{4})=a*sin(\frac{\pi}{8})=4 \] So \(a=4/sin(\frac{\pi}{8})\)
That makes the amplitude of \(g(\theta)\) equal to \(2/sin(\frac{\pi}{8})\)

Answer 4

Seems, I made a typo there. Period of \(f(\theta)\) should be \(\pi\).
On the bright side, it'll be good exercise for you to redo the same steps :P

Answer 5

Awesome job thank you @math&ing001

Answer 6

Don't mention it :3