Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (ray1998):

Please help! Will give fan and medal. A set of data has a normal distribution with a mean of 47 and a standard deviation of 9. Find the percent of data within the following interval. From 20 to 74. The percent of data within the given interval is ___% Thank you in advance!

OpenStudy (misty1212):

HI!! you can use this but it will take two steps http://stattrek.com/online-calculator/normal.aspx

OpenStudy (misty1212):

put in 47 for the mean, 9 for the standard deviation, and 20 for the normal random variable

OpenStudy (ray1998):

Hi! Okay, thank you so much!! What would I put in for the probability?

OpenStudy (misty1212):

you get \[P(x<20)=.00135\] then to it again using 74 for the random variab,le

OpenStudy (misty1212):

subtract \(.00135\) from what you get for \(x=74\)

OpenStudy (misty1212):

hope it is clear leave the \(P(X\leq x)\) blank that is what you are looking for

OpenStudy (ray1998):

So, 0.00135 - 0.99865= -0.9973?

OpenStudy (misty1212):

other way around

OpenStudy (ray1998):

Oh, alright

OpenStudy (misty1212):

or just take your answer and make it positive

OpenStudy (ray1998):

Alrighty :) thank you so much! Are there any other steps?

OpenStudy (misty1212):

nope that is it unless you have to convert it to a percent

OpenStudy (misty1212):

oh yeah you do

OpenStudy (misty1212):

\[99.73\%\]

OpenStudy (ray1998):

Alrighty, thank you very much!!!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!