Please help! Will give fan and medal. A set of data has a normal distribution with a mean of 47 and a standard deviation of 9. Find the percent of data within the following interval. From 20 to 74. The percent of data within the given interval is ___% Thank you in advance!
HI!! you can use this but it will take two steps http://stattrek.com/online-calculator/normal.aspx
put in 47 for the mean, 9 for the standard deviation, and 20 for the normal random variable
Hi! Okay, thank you so much!! What would I put in for the probability?
you get \[P(x<20)=.00135\] then to it again using 74 for the random variab,le
subtract \(.00135\) from what you get for \(x=74\)
hope it is clear leave the \(P(X\leq x)\) blank that is what you are looking for
So, 0.00135 - 0.99865= -0.9973?
other way around
Oh, alright
or just take your answer and make it positive
Alrighty :) thank you so much! Are there any other steps?
nope that is it unless you have to convert it to a percent
oh yeah you do
\[99.73\%\]
Alrighty, thank you very much!!!
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