Question

help?

Answer 1

I have the mid value which is 32. I got that by adding the two tides 12+52 then divided by 2 and got 32. Now what's next?

Answer 2

@Michele_Laino

Answer 3

(¬‿¬)

Answer 4

I know that the relative variation can be expressed like this ratio:
\[\frac{{level\;difference}}{{time\;difference}}\]

Answer 5

hmm but whats the overall formula that we would use?

Answer 6

what do you mean level difference? As in 32/ 6 hours 15 minutes ???

Answer 7

@Michele_Laino you there???

Answer 8

yes! sorry I had to answer to my phone

Answer 9

Okay so what do we do next?

Answer 10

sincerely, I don't know, since in my formula doesn't appear a cosine function

Answer 11

please wait a moment

Answer 12

Okay.

Answer 13

@mathstudent55 can you help?

Answer 14

if we refer to a cartesiuan plane, time-level, we have two distinct points:

Answer 15

cartesian*

Answer 16

okay... do you know how we figure this problem out?

Answer 17

so, time difference = 6 hours, and level difference =40 feet

Answer 18

so we can write this:
\[\cos \theta = \frac{6}{{\sqrt {{6^2} + {{40}^2}} }} = ...?\]

Answer 19

3 sqrt 409/409???

Answer 20

I got this:
\[\cos \theta = \frac{6}{{\sqrt {{6^2} + {{40}^2}} }} = 0.14834\]
and the requested law, is:
\[\cos \theta = \frac{{time\;difference}}{{\sqrt {{{\left( {time\;difference} \right)}^2} + {{\left( {level\;difference} \right)}^2}} }}\]

Answer 21

Why didn't you use this formula?: y = a sin b(x±h) ± k

Answer 22

substantially I have used such formula, since your formula is a more general formual.
If we set b=1, k=0,
\[\begin{gathered}
a = \sqrt {{{\left( {time\;difference} \right)}^2} + {{\left( {level\;difference} \right)}^2}} \hfill \\
y = time \hfill \\
\end{gathered} \]
and h= \(\pi /2\)
we get my formula

Answer 23

formula*

Answer 24

Oh really? Okay! Thanks

Answer 25

:)