Question

help?

Answer 1

cot theta = cos theta / sin theta

so\[1+ \cos ^{2}\theta /\sin ^{2}\theta] \[[1+ \cos ^{2}\theta /\sin ^{2}\theta] = (\sin^2 \theta + \cos ^2 \theta)/ \sin^2\theta = 1/\sin^2 \theta = cosec^2\theta \]

hence proved.... the result is obtained

Answer 2

i hope u understood this

Answer 3

Wait can you come back because I can't see the whole statement... @ribhu

Answer 4

okay..
\[step 1 : \cot \theta = \cos \theta/\sin \theta \]

Answer 5

replace this is the identity on the left side.

Answer 6

then

Answer 7

\[1+ (\cos^2\theta/\sin^2\theta )\]

Answer 8

\[(\sin^2\theta + \cos^2\theta)/ \sin^2\theta
{ taking LCM} \]

Answer 9

\[1/\sin^2\theta\]

Answer 10

\[= cosec^2 \theta = result\]

Answer 11

i hope now its clear!!

Answer 12

Yes very clear, thank you! Now not to sound a little ehhh but Can I just put "cosec^2(theta) in teh calculator to get the result or is it the final result?

Answer 13

this is the final result.... chill

Answer 14

bwahha just making sure, thank you! Wait but before you go could you look at this one? no one could figure it out earlier..

Answer 15

this proves the identity also...
you can check this using calculator... just check with theta = 30 degrees, you will get left hand side equal to right hand side.

Answer 16

yes u need to have a function for this..

Answer 17

There isnt a formula for this problem that I can follow?

Answer 18

nah

Answer 19

Lol Okay thank you!

Answer 20

@Photon336 would you like to assist me on this?