Question

would you mind helping me out please:) fan and medal :)

Answer 1

Do you know the midpoint formula and the formula to find the radius?

Answer 2

\(\textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
P&({\color{red}{ -10}}\quad ,&{\color{blue}{ -2}})\quad
% (c,d)
Q&({\color{red}{ 4}}\quad ,&{\color{blue}{ 6}})
\end{array}\qquad
% coordinates of midpoint
\left(\cfrac{{\color{red}{ x_2}} + {\color{red}{ x_1}}}{2}\quad ,\quad \cfrac{{\color{blue}{ y_2}} + {\color{blue}{ y_1}}}{2} \right)\impliedby center\)

Answer 3

Just what I was fixing to put, thanks for putting it into a better form jdoe :)

Answer 4

=)

Answer 5

now, the radius is the "distance" between, the center and and endpoint
so, use the distance equation to get the radius :)

Answer 6

to get the center, yes
tis just the MidPoint formula, is all

so.. what does that give you for the center anyway?

Answer 7

hmmmm one sec

Answer 8

\(\textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
P&({\color{red}{ -10}}\quad ,&{\color{blue}{ -2}})\quad
% (c,d)
Q&({\color{red}{ 4}}\quad ,&{\color{blue}{ 6}})
\end{array}\qquad
% coordinates of midpoint
\left(\cfrac{{\color{red}{ 4}} + {\color{red}{ (-10)}}}{2}\quad ,\quad \cfrac{{\color{blue}{ 6}} + {\color{blue}{ (-2)}}}{2} \right)
\\ \quad \\
\left( \cfrac{-\cancel{6}}{\cancel{2}}\quad ,\quad \cfrac{\cancel{4}}{\cancel{2}} \right)\implies (-3,2)\)

Answer 9

\(\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ -3}}\quad ,&{\color{blue}{ 2}})\quad
% (c,d)
&({\color{red}{ -2}}\quad ,&{\color{blue}{ -10}})
\end{array}\qquad
% distance value
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)

that'll give you the radius