Mathematics
4 Online
OpenStudy (exoexoexo):
if x-5, 2x, and 4x+6 are the first 3 terms of an arithmetic sequence, find x and the values of the three terms
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satellite73 (satellite73):
what is \(2x-(x-5)\)?
OpenStudy (exoexoexo):
x-5
OpenStudy (exoexoexo):
wait x+5
satellite73 (satellite73):
yes
satellite73 (satellite73):
so the difference between the first two terms is \(x+5\)
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satellite73 (satellite73):
now what is \(4x+6-2x\)?
OpenStudy (exoexoexo):
2x-6
satellite73 (satellite73):
i agree
and since it is arithmetic, the differences must be the same
to find \(x\) solve \[x+5=2x-6\]
OpenStudy (exoexoexo):
x=11
satellite73 (satellite73):
that is what i get too
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satellite73 (satellite73):
now that you know \(x=11\) finding the value of the first 3 terms should be easy enough right?
OpenStudy (exoexoexo):
\[a _{1}=6\]
\[a _{2}=22\]
\[a _{3}=50\]
OpenStudy (exoexoexo):
that doesn't seem right
satellite73 (satellite73):
no it doesn't does it
OpenStudy (exoexoexo):
can we try
\[2x=(x-5)+(2-1)(x+5)\]
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OpenStudy (exoexoexo):
that doesn't work out either
satellite73 (satellite73):
hold on let me think see if i can figure out what is wrong with this method
common differences must be equal
satellite73 (satellite73):
oh cause i am an idiot
satellite73 (satellite73):
i wrote \[x+5=2x-6\] but it really should have been \[x+5=2x+6\] doe
satellite73 (satellite73):
since \(4x+6-2x=2x+6\)
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satellite73 (satellite73):
works now i bet
OpenStudy (exoexoexo):
x=-1
satellite73 (satellite73):
yes, now try it, see if it works
OpenStudy (exoexoexo):
thank you