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Physics 20 Online
jabez177 (jabez177):

A mechanic uses a mechanical lift to raise a car. The car weighs 12,500 N. The lift raises the car 2.25 m in 10 seconds. How much power was used to accomplish this task? A. 2812.5 W B. 1.8 x 10-4 W C. 5556 W D. 28.125 W

jabez177 (jabez177):

@sweetburger What's the formula again for this?

jabez177 (jabez177):

@Hayhayz

jabez177 (jabez177):

@jtug6

Hayhayz (hayhayz):

@sammixboo

jabez177 (jabez177):

@pooja195

pooja195 (pooja195):

Do you know the formula you would use? Any ideas?

jabez177 (jabez177):

work / time

jabez177 (jabez177):

times the distance or wait. let me google it real quick

jabez177 (jabez177):

|dw:1464747294072:dw|

pooja195 (pooja195):

Since it says power=F x V What is our force?

jabez177 (jabez177):

12,500

pooja195 (pooja195):

What's our velocity?

jabez177 (jabez177):

2.25 x 10

pooja195 (pooja195):

Wait I screwed up sorry >.< scratch that First you need to use the formula for how much "work" was done (btw im lookin at my physics notes >.> i hated phyiscs) work=force times distance force=? distance= ?

OpenStudy (jtug6):

i solved it but i could be wrong too. i'll give u my answer pooja and you can see if it's right =)

pooja195 (pooja195):

Alright :) (don't post it here message it) and @jabez177 did you fall asleep?

jabez177 (jabez177):

So 12,500 x 2.25m = 28,125

jabez177 (jabez177):

im almost falling asleep haha

pooja195 (pooja195):

Good now we would use the formula \[\huge~\rm~\bf~Power=\frac{ Work }{ Time}\]

jabez177 (jabez177):

\[28,125\div10=2812.5\]

pooja195 (pooja195):

Perfect and that would be our answer :-)

jabez177 (jabez177):

Now I see. I should have written down some notes when my teacher taught this...

jabez177 (jabez177):

Thank you, Pooja! :)

ILovePuppiesLol (ilovepuppieslol):

O_O

pooja195 (pooja195):

:P oh well have fun suffering with physics x'D

pooja195 (pooja195):

You're welcome :-)

jabez177 (jabez177):

fr haha :')

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