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Verify the identity. cot (x-π/2) = -tan x
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depends on what you get to use the cofunction identity tells you \[\cot(\frac{\pi}{2}-x)=\tan(x)\] and cotangent is an odd function so \[\cos(x-\frac{\pi}{2})=-\tan(x)\]
I don't get it.
satellite73 explained it already, cotangent is an odd function so, \[\cot(-y)=-\tan(y)\]
@satellite73 sorry here you missed the cot and wrote cos << and cotangent is an odd function so cos(x−π2)=−tan(x) >> - this above wann being cot(x-pi/2)=-tanx
so cot(π/2-x) = tanx?
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yes
that is a "cofunction" identity like \[\sin(\frac{\pi}{2}-x)=\cos(x)\] and \[\csc(\frac{\pi}{2}-x)=\sec(x)\] if you draw a right triangle you will see why
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