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Mathematics 8 Online
OpenStudy (christos):

diverging series * diverging series = diverging series ?

OpenStudy (zarkon):

depends on what you mean if \(\sum a_n\) and \(\sum b_n\) both diverge then it is possible that \(\sum a_n b_n\) converges

OpenStudy (christos):

thanks a lot

OpenStudy (zarkon):

for a simple example take \(a_n=b_n=\frac{1}{n}\)

OpenStudy (christos):

but if they diverge to infinity then the product will diverge 100% right

OpenStudy (christos):

aha

OpenStudy (zarkon):

\[\sum_{n=1}^{\infty}\frac{1}{n}=\infty\] \[\frac{1}{n}\frac{1}{n}=\frac{1}{n^2}\] \[\sum_{n=1}^{\infty}\frac{1}{n^2}=\frac{\pi^2}{6}\]

OpenStudy (christos):

so I guess there is no algebra to be made with divergence and convergence

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