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Chemistry 8 Online
OpenStudy (marcoreus11):

I need help can show teach me how to do them or link a video that's is easy to understand?

OpenStudy (plainntall):

Perhaps it will help if we review the definition of pH and pOH. The relationship between pH and pOH is pH + pOH = 14 pH = -log[H+] or in water or aqueous solution -log[H3O+] pOH - -log[OH-] = That should be all you need plus a calculator that does log and inverse log For the first one you have \[[H ^{+}] = 4.5\times10^{-6}\] pH=-log[4.5xqo^-6] = 5.35 pOH=14-5.35=8.65 [OH-]=10^-8.65 =2.24x10^-9 It looks like you got the right answers so all you need to do is keep doing the math.

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