Suppose that a cyclist began a 341 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5 hr and the car traveled 37.2 mph faster than the bicycle, find the average rate of each.

Question

Suppose that a cyclist began a 341 mi ride across a state at the western edge of the​ state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 5.5 hr and the car traveled 37.2 mph faster than the​ bicycle, find the average rate of each.

tootsi123 · Answer

The​ car's average rate is ___mph.
​(Type an integer or a​ decimal.)
The​ bicycle's average rate is ____mph.

thereisnousername · Answer

Let cyclist speed be x mph
 car speed = (x+42.7)mph
both of them take the same time to meet =5.5 hours
distance: 341 miles
combined speed: 2x+42.7
formula: t=d/r
5.5=341/(2x+42.7)
5.5(2x+42.7)=341
11x+85.4=341
11x=341-85.4
11x=255.6
x=23.24 Cycle speed,
23.24 + 42.7=65.94 Car speed

23.24= cycle speed
65.94= car speed

tootsi123 · Answer

Thank 
you!

tootsi123 · Answer

attachment

tootsi123 · Answer

New question above. Please help.

thereisnousername · Answer

open a new question, so there isn't so much lag, and tag me

tootsi123 · Answer

Okay I will try. :)