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I get a little confused by these. For π(π₯) = π₯ β 2, find π^β1(π₯). Then find π(π^β1(8))
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I know that π(π^β1(8)) is 8
my answer is either π^β1(π₯) = βπ₯ + 2 ; 8 or f^-1(x)=x+2;8
I'm just not sure which one
@Vocaloid could you perhaps clarify this for me?
do you know how to solve y=x-2 for x?
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like to get x by itself?
yeah x=2+y
cool now that is basically it interchange x and y and you have your inverse function
y=2+x or you can write as y=x+2
where you can replace y with f^(-1)(x)
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Right. So would it be f^-1(x)=x+2;8?
yes y=x-2 y+2=x so f^(-1)(x)=x+2
Awesome, thanks so much!
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