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Mathematics 8 Online
OpenStudy (allieeslabae):

Check these please?!

OpenStudy (allieeslabae):

@haleyelizabeth2017

OpenStudy (allieeslabae):

@Michele_Laino

OpenStudy (michele_laino):

the sequence of numbers: 22, 17.6, 14.05 are a geometric series, whise constant is: \(17.6/22=14.05/22=0.8\) so the first square whose length is \(10\) inches, will be such that: \[10 = 22 \cdot {0.8^{\left( {n - 1} \right)}}\] please solve for \(n\)

OpenStudy (michele_laino):

oops.. I meant \(17.6/22=14.05/17.6=0.8\)

OpenStudy (allieeslabae):

Oh wow.. so thats the first one? how about the second and third.

OpenStudy (allieeslabae):

n is aprprox 4.53

OpenStudy (michele_laino):

numbers: \(-4,2,8,...\) are an arithmetic series, whose constant is \(d=2-(-4)=8-2=6\) so the 50th term is: \[{a_{50}} = {a_1} + \left( {50 - 1} \right)d = - 4 + \left( {49 \times 6} \right) = ...?\]

OpenStudy (allieeslabae):

290

OpenStudy (michele_laino):

finally third question: the sequence \(-4,8,-16,32,...\) ia a geometric sequence, whose first term is \(-4\) and the constant is \(2\), so the 20ty term is given by the subsequent computation: \[{a_{20}} = {a_1} \cdot {q^{\left( {20 - 1} \right)}} = - 4 \cdot {2^{18}} = ...\]

OpenStudy (allieeslabae):

-1048546 ??

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