Question

@calculusxy

Answer 1

O..m.g it won't post D:

Answer 2

can you write out the problem?

Answer 3

I am, and brb let me refresh

Answer 4

Okay Perform the indicated operation.\[\frac{ y }{ y-5 } + \frac{ 5 }{ 5-y}\]

Answer 5

what's the common denominator?

Answer 6

5

Answer 7

not really. look at the denominators carefully.

Answer 8

you have the denominators of \(y-5\) and \(5 - y\). since they don't share anything with each other (like one is not a multiple of the other), the common denominator would be \((y-5)(5-y)\).

Answer 9

Ooooh

Answer 10

Or just multiply by -1 ;]

Answer 11

;]

Answer 12

you can make it easy
that's right (y-5) isn't same as (5-y)
but you can take out the negative one \[(5-y)= -(-5+y)\]

Answer 13

\[\frac{ y }{ y-5 } \color{Red}{+}\frac{5}{-(y-5)} = \frac{ y }{ y-5 }\color{red}{ -}\frac{ 5 }{ y-5 }\]
(-5+y) is same as (y-5)

Answer 14

OOoooh so now it's subtracting? ;3

Answer 15

so since the common denominator is \((y-5)(5-y)\). what you need to do is make sure to have each of the fractions have that common denominator.
\[\frac{y}{y-5} \rightarrow \frac{y\color{red}{(5-y)}}{(y-5)\color{red}{(5-y)}}\]

Answer 16

so i think @Nnesha got this. i don't want to interfere, or else u r going to get confused

Answer 17

Omg i think i get it now so since the denominator is subtracted and the to we subtract too so it would look like this?
\[\frac{ y-5 }{ y-5 }\]

Answer 18

Yep !

Answer 19

oh no no no cary one please.
that's another way to solve this question.

Answer 20

Then simplify it.

Answer 21

o.mg. i mean \[\frac{ y-5 }{ 5-y }\]

Answer 22

on*

Answer 23

First one was correct..