Question

What is the equation of the following graph?

http://i729.photobucket.com/albums/ww292/akatushi101/vaahahaa.gif

Answer 1

you know the name of the shape?

Answer 2

Hyperbola

Answer 3

ok good
and can you see the center of it?

Answer 4

Yeah

Answer 5

Basically I will be doing these in my next unit but have to wait till I learn them. My teacher said she will be throwing things in there to see what we need to know.

Answer 6

what do you think the center is?

Answer 7

1,2

Answer 8

ok good we we are almost done
standard form for hyperbola with center \((h,k)\) is either \[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\] or \[\frac{(y-h)^2}{a^2}-\frac{(x-k)^2}{b^2}=1\]
do you know which one this will be?

Answer 9

Top

Answer 10

Hint: Which vertices are further from the center of this hyperbola than are the other set of vertices?

Answer 11

yes, the top one

Answer 12

Can you now read "a" and "b" from the TOP equation, or from the graph itself?

Answer 13

put \(h=1,k=2\)
now all that is left is \(a\) and \(b\)

Answer 14

Im trying to get some paper out as well a pen

Answer 15

\(a\) is the distance from the center to the end of that rectangular box (going right or left) and \(b\) is the distance from the center to the end of the box going up or down

Answer 16

so a is 10

Answer 17

no

Answer 18

not the total length of the box, that is 10
the distance from the center to the end of the box, or half the total length

Answer 19

oh 5

Answer 20

right \(a=5\)

Answer 21

and \(b\)?

Answer 22

b is 2

Answer 23

right
done

Answer 24

well, done as soon as you put those numbers in here \[\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\]

Answer 25

(x-1)^2/5^2-(y-2)^2/2^2=1

Answer 26

satellite you on facebook haha

Answer 27

appreciate it a lot everyone

Answer 28

you got it
no
well not under "satellite" facebook is for old people, i am a fan of instagram

Answer 29

hit me up on instagram, its fd3s_rx7_man

Answer 30

says account is private

Answer 31

oh, can i still accept