need help
@mathmale
Please post your question up front, OK? Then I'd be in a better position to decide whether I can or want to help with it.
\[-5x-7\le-3(x+1)+2\]
okay
I see multiplication in the right hand side of your inequality. Please carry out this multiplication.
\[-5x-7\le-3x-1+2\] Right?
Where did that -1 come from?
First distribute ---> -3(x+1) = -3x -3 Then combine like terms ... Note i would make the "x" term positive -7 +3 -2 < -3x + 5x -6 < 2x Divide by 2 -3 < x
the -3 * (+1)
whoops
wouldn't that be -3?
yep just realized that
So, your \[-5x-7\le-3(x+1)+2\]
becomes what?
\[-5x-7\le-3x-3+2\] I think
You think? What 'd you get were y ou to combine -3 and +2? Do combine them, please.
\[-5x-7\le-3x-1\]
Nice. Now we need to solve for x. Think about how you might do that. It'd be great if your initial aim were to give x a positive (not a neg) coefficient.
add the 5x to the -3x right?
Actually, you need to treat both sides of this inequality the same. Therefore, add 5x to both sides and simplify your result. Your result?
\[-7\le+2x-1\]
two more steps and you are done
add 1 to -7?
Please note: whatever you do to one side of your inequality, you MUST do to the other side. So, add 1 to both sides and then simplify the result.
\[-6\le2x\] Then \[-3\le x\]
is that right?
Surely looks it! Why don't you check it yourself? Choose any test number for x and substitute that number for x in the inequality. Is the inequality then true or false?
it is it
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