There are three different positive integers whose reciprocals add up to 1. What is the product of those three integers?
Tried anything?
Reciprocals means this: 5/4 reciprocal is 4/5
well i mean at first i thought the three numbers were 3. But then i saw that they were all supposed to be different
and @aaron i know what a reciprocal is
As a start, setup an equation
1/z+1/x+1/x=1 x*x*x=?
Let the 3 number be x,y,z respectively. So, \[\frac{ 1 }{ x } + \frac{ 1 }{ y } + \frac{ 1 }{ z }= 1\]
Take the LCM \[\frac{ yz }{ xyz } + \frac{ xz }{ xyz } + \frac{ xy }{ xyz } =1\]
yeah that's where i'm stuck
product xyz = yz+xz+xy
the only saving grace is that they're integers
xyz = yz+xz+xy Now we have to use the try and error method we have substitute x , y and z with number such that the sum of their reciprocal is 1.
I think I found the 3 numbers there 2,3,and 6 1/2 + 1/3 + 1/6 LCM = 6 3/6 + 2/6 + 1/6 3+2+1 = 6 and 6/6 = 1
looks good, but are there any others?
is it 2,3, and 6? because 1/2=3/6 and 1/3=2/6 and 2/6+3/6+1/6=6/6=1?
Yep! :)
Nice
thank you so much!
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