What is the product in simplest form? State any restrictions on the variable. 2x-8/x^2-16 • x^2+5x+4/x^2+8x+16
Wow... this is gonna be a mess... how are your factoring skills ??
Just to check ... is the problem the same as \[ \frac{2x-8}{x^2-16} \cdot \frac{x^2+5x+4}{x^2+8x+16}\]
@cruffo yea that's the problem
ok. I would suggest factoring all numerators and denominators first, in case we can simplify, and to check for those "restrictions" the question asked about.
Can u explain or show me how to factor the numerators and denominators? Idk how to do that part.
\[\frac{ 2(x-4) }{ (x-4)(x+4) } \times \frac{ (x+4)(x+1) }{ (x+4)(x+4) }\]
use formula difference of two squares
Can you simplify it?
What Aveline's answer is showing is the factored form. She had to use a number of techniques to do that. Do any of those factorization **not ** make sense?
That makes sense, what do I do after its in factored form?
what mean restrictions in this case ? how you think ?
Would the answer be 2=x+1?
The "restrictions" that they are talking about are numbers that make the denominator in either fraction 0. Remember : #/0 is undefined.
No, the goal is not to "solve", but to multiply.
yes cruffo you are right
Ah okay sorry I'm so confused
the denominator zero make the fractions undefined
For the point of Aveline's answer, what numbers make the denominator 0? Hint, there are two such numbers...
On the left side, cross off the two (x-4)'s on the top and bottom. They equal 1 anyway so they cancel out. On the right side, do the same thing with the two (x+4)'s: \[\frac{ 2 }{ (x+4) } \times \frac{ (x+1) }{ (x+4) }\]
This is too busy...
Okay so... 2 and 1 would be the restrictions?
@cruffo am I right?
Well the equation simplifies to \[\frac{ (2)(x+1) }{ (x+4)(x+4) }\] If we plug in -4 for x, the bottom of the equation is equal to 0. Therefore, the restriction is x=-4 Take a look for yourself. X can not equal -4 https://www.desmos.com/calculator/ofx8rjslpa
Okay I got it, thank you guys so much !! Aveline could you please help me with one more problem?
@aveline please help !! Solve the following equation and check the solution. 4/x-2 = x-1/x-2
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