scatter plot help needed
What is your question?
thanks this is really confusing and ill love it if you please explain how to solve this
Let's draw a line of best fit. Take a look here at what I drew http://prntscr.com/bc2s4c
Do you know how to find the y-intercept (b) and the slope (m) to create our equation?
i know its y=mx+b i think but i dont know what to do at this point
Yes, the equation we are using is y = mx + b, and it's OK if you don't know, I'll teach you. We are going to start by finding the y-intercept (which is b). The y-intercept is the point where the line crosses over the y-axis. Can you give estimate where my line I drew crosses over the y axis? http://prntscr.com/bc2s4c
is it about 0,1.10? and thanks again for helping me
Yes, 1.10 will be our y-intercept, so let's put it for b in the equation. y = mx + 1.10 Now we need to find the slope. Do you know the formula we can use to find the slope?
nope :/
Ok, that's fine. The formula to find the slope is \(\tt \dfrac{x-x_2}{y-y_2} = m \). To use this slope we need to pick two points on the line and plug them into the equation. Let's use the points (8, 1.32) and (3, 1.2) where \(\tt 8 = x\), \(\tt 1.32 = y\), \(\tt 3 = x_2\), and \(\tt 1.2 = y_2\)
\(\tt \dfrac{x-x_2}{y-y_2} = m\) \(\tt \dfrac{8-3}{1.32-1.2} = m\) Do you know how to solve this?
yes, but a question i had was how did you decide to pick those points
I am so sorry. The y is supposed to be on top, so you will be solving \(\tt \dfrac{1.32-1.2}{8-3} = m\)
Hold on, I think I completely screwed something up... Please, don't continue while I figure out my mistake. I am so sorry!
no biggie! take your time :)
LOL this has to be some kind of troll question ;)
XD
It says it is in thousands, but it is in millions on the graph. The y intercept is supposed to be a decimal, but in the answers it isn't xD
Is it?
LOL
lol im so confused with the question and everything lol
This whole question is screwed up, hah
pretty much, lol the answers are kinda in decimals i guess
And the points only go up 8 years, not 10 What is this??
Please do not cheat on your interim assignment. That is there to test you on your knowledge on what you have learned and how much you have progressed.
This question shouldn't even be on any test! AH
im not cheating im genuinely confused, im learning off of CompassLearning.com and literally that school doesnt help me at all and im going to this website for help and knowledge. if i wanted to cheat id go to a calculator @jabez177
There is a few things wrong with this problem, so no wonder why
If you can report the question to your teacher or someone, please do http://prntscr.com/bc3096
thanks i will right now, if it werent for you guys i wouldnt have known that this question is messed up, im going into high school next year and i dont want to be held back for the lack of good curriculum on the website im learning from. i honestly try my hardest but its reflecting the teaching flaws
heres another one, is this one messed up too?
That one looks better, lol
btw theres lines between each number on the x axis its just the screenshot looks crappy
But the slope I am getting isn't in one of the choices
now for this one the y intercept is at 0,110 but which two points do i pick to find the slope
Any two points on the line of best fit
the line of best fit would be like this right
Yes, then pick two points on the line and plug them into the equation
troll ._.
can you stop this is a serious question i need help @Comrad
The issue is that the y scale on the graph is in millions while the linear equation models the y value in thousands in other words y = 1.12 on the graph means y = 1.12 million (aka 1,120,000) y = 1.12 from the equation means 1.12 thousand (aka 1,120)
does this mean that this equation is not solvable ?
no it means that we have to rescale things
well i already guessed an answer, thanks for trying to help to those who tried
I'm still not getting the slope they list, so there's probably a typo somewhere
Trust me, I been trying.. There is something wrong with this problem, lol
thanks i appreciate it :)
for your new problem you can eliminate the two that don't have 110 then, the point on x=8 is a bit too high up to use for the line of best fit so I tried the x=7 and x=0 the y's of those are 136 and 110 respectively 36 - 10 = 26 taking into account that there is that slightly higher point (and for the sake of mental math) I went with 28 divided by 7 to get the slope This should get you to a proper answer for once
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