Question

A hobby rocket reaches a height of 72.3 meters and lands 111 meters from the launch point. What was the angle of launch?

Answer 1

@amistre64 @Compassionate @inkyvoyd

Answer 2

@sammixboo @ShadowLegendX @sleepyjess

Answer 3

@Anaise

Answer 4

Well you've looked at google, what part do you still not understand? I'll see if I can help :)

Answer 5

I used the Kinematics equations but I end not being able to find the answer

Answer 6

The equations I have now are
72.3 = 1/2 * 9.8 * t^2 (reverse throwing upwards, vertical motion)
\[v_{x}\] *t = 55.5

Answer 7

I forgot that I failed physics...

Answer 8

Lol

Answer 9

gimme a sec ill see if i can solve it

Answer 10

Will I'm not the best at physics but I can try! :>

Answer 11

@Lowkey.S We just got done scolding someone for copy pasting google.

Answer 12

Argh
I surrender

Answer 13

na justin (jtug6) is typing
there is hope :D

Answer 14

Ok so i had to look some stuff up myself but you need to be able to first find the horizontal and vertical components of the projectile so that you're able to use these to find the angle between the distance covered and the height at which it reaches. There's a couple of things we need to first cover over. First and furthermost you need to apply the equation:

d(distance) = Vi(initial velocity) + 1/2(a)(t^2) where a is the acceleration of the projectile and t is the time.

Answer 15

This is the appropriate equation we need to use because all the variables are there except our t time. This equation is used to determine the time it takes for the projectile to reach its maximum height, which is approximately half of the total time the shuttle is in the air. So what is the distance, inital velocity, acceleration then?

Answer 16

and he's offline ;-;

Answer 17

rip hopefully he comes back lol

Answer 18

thanks for the effort tho @jtug6 :D

Answer 19

no problem ^_^ love me some physics

Answer 20

We should draw it first