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Calculus1 10 Online
OpenStudy (feynanon):

A line l intersects the parabola y=x^2 at two points, (a, a^2) and (b, b^2) b>a. 1. Calculate the area bordered by the line and the curve: 2. If l is perpendicular to the tangent line to the curve at (a, a^2) Express a in terms of b. 3. When (2.) holds true, find the minimum area m of S in terms of b. For what value of b, the area is minimized? This is what I got until now http://puu.sh/ph1Dl/9fda67a36e.jpg mind correcting me?

OpenStudy (loser66):

To me, for part1) you have equation of the line passes through A (a, a^2) and B(b,b^2) is \(y_{line}= (a+b)x -ab\) but the area bordered by the line and the curve is \[\int_a^b upper - lower = \int_a^b ((a+b)x-ab -x^2)dx\]

OpenStudy (loser66):

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OpenStudy (loser66):

for part 2) the line tangent to the curve has slope = 2x Hence at (a, a^2) , its slope is \(m_1 = 2a\) then perpendicular to the tangent to the curve at (a,a^2) is \(m_2= \dfrac{-1}{2a}\)

OpenStudy (loser66):

and line from part 1 has the slope is a+b, hence \(a+b =\dfrac{-1}{2a}\) you can solve for a.

OpenStudy (mathmale):

Interesting problem. Please, @feynanon, give us a progress report. How much of this problem have you been able to complete? What do you still need help with, if anything?

OpenStudy (feynanon):

Hello, @Loser66 and @mathmale Thank you so much for your responses! This is how I ended up solving the problem, with some help. Even though I don't know if it's correct, would you mind taking a look at my solution? (excuse my handwriting) 1st: http://puu.sh/ph1Dl/9fda67a36e.jpg 2nd: http://puu.sh/pihEi/14bda90ae2.jpg

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