Question

sarah took the advertising department from her company on a round trip to meet with a client. including sarah a total of 6 people took the trip.she was able to purchase coach tickets for $250 and first class tickets for $940.she used her total budget for airfare for the trip,which was $4260.how many first class tickets did she buy? how many coach tickets did she buy?

Answer 1

It helps to write things out.
First let's make up two variables
Coach Tickets = C
First Class Tickets = F

Next write down the given relationships

6 people mean 6 tickets giving us
C + F = 6

Cost is the number of First Class Tickets times $940 plus number of Coach tickets times $250 with the total equal to $4260

$940F+$250C= $4260

Now you have two equations solving
C + F = 6 for either C or F will allow you to substitute it into the second equation giving you only one variable to solve for. Once you have that variable subtract it from 6 to get the second.

Answer 2

so the answer is 6 for both?

Answer 3

That would give 12 people on the trip.

Solving C+F=6 for C gives C=6-F now substitute it into

$940F + $250C = $940F +$250(6-F) = $4260 What does F equal?

Answer 4

250(6-f)

Answer 5

940F + 250(6-F)=4260
940F + 1500 - 250F = 4260 (multiplying 250x6 and 250xF)
(940-250)F + 1500 = 4260
690F + 1500 = 4260
690F + 1500 -1500 = 4260 -1500 (subtract 1500 from both sides)
690F=2760
F = 2760/690 = 4

Now that we know F we can find C
C=6-F = 6-4 = 2

4 first class tickets and 2 Coach

Answer 6

1. read the problem
2. make variables
3. right down relationship in equation form
4. Solve for one variable
5. substitute for that solved variable
6. Solve for the second variable
5 Solve for the first variable using the second variable

Answer 7

thank you very very much for your time and help :-)

Answer 8

welcome

Answer 9

sorry if i was difficult to work with lol

Answer 10

No reason to apologize. I am helping because I want to. Math is challenging, but it can be fun once you figure it out and that can be difficult.