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Mathematics 18 Online
OpenStudy (niuuu):

hey so this question involves a graph and I don't understand what n does at all

OpenStudy (niuuu):

OpenStudy (niuuu):

ganeshie8 (ganeshie8):

Hey

OpenStudy (niuuu):

@ganeshie8 hi? can you help, id love you forever

OpenStudy (p0sitr0n):

there is no n is the formula... is it the exponent?

OpenStudy (niuuu):

@P0sitr0n ok yeah It showed up weird right then but that equation should be f(x)=a(x+k)^1/n+c

OpenStudy (mathmale):

Double check the original question: instead of just a line, wasn't there any character to mark where that "n" should go? You could experiment, letting n take on each of the given 3 possible values, one at a time, and determine that way which n value reproduces the function behavior shown in this graph. I note that if k=-5, y=2, meaning that c=2; thus, you have y=a(x-5)^(n) + 2, or possibly y=a(x-5)^(1/n) + 2.

OpenStudy (niuuu):

@mathmale how would I if the n in that second equation is a negative or a positive and or even and odd

OpenStudy (mathmale):

I don't see the answer right off, which is precisely why I've suggested that you experiment. Suppose you use 'n' to represent the exponent; then graph the 3 cases: 1. n is neg. odd (e. g., -3) 2. n is neg. even (e. g., -2) 3. n is pos. even (e. g., 2) If you have a graphing calculator and know how to use it properly, it should not take you long to graph the given function several times, once for each of the n values proposed. The idea is to determine which n value produces a graph similar to the one given you.

OpenStudy (jdoe0001):

@niuuu seems to me, you're missing a few characters from the posting namely, the exponent of the parenthesized group

OpenStudy (mathmale):

I agree that something is missing from the equation given in the illustration. I've been suggesting that you assume the missing character is n, and then graph the function for 3 different n values (see above). Could you go back to the original illustration and double check what the exponent given there actually is?

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