Question

How to solve 192 = x^2 + 12x

Answer 1

You have to get x by its self...
\[192=x ^{2}+12x\]
then \[x ^{2}\] Counts as 1 x, so
\[x ^{2}+12x= 13x ^{2}\] \[192=13x ^{2}\]
Now, to get rid of the \[x ^{2}\] You need to square root it, so
\[\sqrt{192}=\sqrt{13x}=13.856\]
Round to the nearest tenth
13.9=13x
Then divide
\[13.9\div13x=1.069\]
Round to the nearest tenth
x=1.1

Answer 2

Hopefully I did that correctly

Answer 3

No that's not the answer I got

Answer 4

That's wrong @Kittyloli
You cannot add x^2 and x, both are different.

Answer 5

HECK

Answer 6

This is why I can't do math

Answer 7

\(x^2+12x-192=0\) Can you think of two numbers that multiply to -192 but add to 12?

Answer 8

192 = x^2 + 12x
Rewrite the equation as
x^2 +12x -192 =
In this equation a=1 b=12 and c=-192
Do you know the quadratic formula?

Answer 9

oh I do! Thank you so much I think I got it now

Answer 10

Wow okay Abby - that was easy!!

Answer 11

Try factorization
This rule is called middle term factorization

factorize 192

You get 192 = 2*2*2*2*2*2*8
Now arrange 192 as sum or subtraction of the terms to btain 12
You see 2*2*2*3-2*2*2=24-8=12

Now 12x= 24x-8x

Now, \[x ^{2} + 12x-192=0\]
or,
\[x ^{2}+ 24x-8x-192=0\]
or,
x(x+4)-8(x+24)=0
or,
(x+24) (x-8)=0
or,
x=-24,8

@wolf1728, I don't think quadratic equation is an intelligent way to answer this simple question. Use that rule when you cannot factorize easily.

Answer 12

@Dustin_Whitelock 24x — 8x equals 16x though

Answer 13

@Call_Me_Abby Congratulations, for finding out the intentional mistake. Now since you know how to obtain the answer, do the factorization correctly and get your answer.

Answer 14

Yep I did both your way and the quadratic formula way and got my answer

Answer 15

:)

Answer 16

24 and 8 are NOT the answers
192 factors into 2*2*2*2*3*19

x^2 +12x -192
a=1 b=12 and c=-192
Using quadratic formula:
x = -12 +- sqroot (144 -4*1*-192) / 2*1

x = -12 +- sqroot (144 + 768) / 2

x = -12 +-(30.1993377411)/2

x1= (-12 + 30.1993377411)/2
x1 = 9.0996688706

x2= (-12 - 30.1993377411)/2
x2 = -21.0996688706

Answer 17

I got 9.1, Dustin_Whitelock made the mistake on purpose so they wouldn't be giving out the answer

Answer 18

Okay Abby well I gave out the answers to many decimal places. (Mainly because I thought the equation was already solved.) Anyway 9.1 is one answer and you can see the other one.

Answer 19

Thankss now I know for sure for sure that the answer's right

Answer 20

lol

Answer 21

The actual best method here is completing the square. The middle term is even and the leading coefficient is 1. This is fact. jk

Answer 22

\(192 = x^2 + 12x\)

\(x^2 + 12x - 192 = 0\)

Use the quadratic formula:

\(\large x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2b} \)

\(\large x = \dfrac{-12 \pm \sqrt{(-12)^2 - 4(1)(-192)}}{2(1)} \)

\(\large x = \dfrac{-12 \pm \sqrt{144 + 768}}{2} \)

\(\large x = \dfrac{-12 \pm \sqrt{912}}{2} \)

\(\large x = \dfrac{-12 \pm 4\sqrt{57}}{2} \)

\(\large x = -6 \pm 2\sqrt{57} \)