Question

Line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to Line AB?
5x – 3y = 0
-x + 3y = 0
-5x – 3y = 0
3x + 5y = 0
-3x + 5y = 0

Answer 1

Any ideas?

Answer 2

I think it might be B? But I'm really bad at geometry so I don't know... I need to finish this class for graduation... And this is my second year taking Geometry... Math isn't my strong suit

Answer 3

You're in the second year of class already, you should have a grasp of this question, and the question is very easy

Answer 4

I barely passed the first year...

Answer 5

You just start by finding the gradient first, and then, since the equation of the line that passes through the origin will have a coordinate of (0,0), you will then use \((y-y_1)=m(x-x_1)\) to construct your new equation.

Answer 6

Thank you

Answer 7

@Kittyloli
Use this point-slope form I told you about earlier,
instead use this two-point slope form
\[(y-y1)\div(x-x1) = (y1-y2)\div(x1-x2)\]
Put the coordinates of A and B in x1, y1, x2, y2 resp.

Now you got the equation of your line

Arrange this in the form of ax+by=k
(Note: k may be zero)

Now, k can be any real number, and you get your answer
:)

Answer 8

I got it :3