Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (stryder12345):

PLEASE HELP WILL EARN MEDAL When 27 times x squared times z all over negative 3 times x squared times z to the sixth power is completely simplified, the exponent on the variable z is _____.

OpenStudy (stryder12345):

OpenStudy (stryder12345):

that is the equation that you have to simplify

OpenStudy (sylph):

We don't have to simplify it--you do. We're here to help.

OpenStudy (stryder12345):

i know

OpenStudy (stryder12345):

but i need help on how to simplify it

OpenStudy (stryder12345):

if you could help me then that would be great

OpenStudy (sylph):

This syntax thing is terrible. I'll have to retype everything.

OpenStudy (sylph):

(27 x^2 z)/(-3 x^2 z^2)=(x^2/x^2)×(27 z)/(-3 z^2)=(27 z)/(-3 z^2): (27 z)/(-3 z^2) The gcd of 27 and -3 is 3, so (27 z)/(-3 z^2)((3×9) z)/((3 (-1)) z^2)3/3×(9 z)/(-z^2)(9 z)/(-z^2): (9 z)/(-1 z^2) Combine powers. (9 z)/(-z^2)(9 z^(1-2))/(1 (-1)): (9 z^1-2)/(-1) 1-2-1: (9 z^-1)/(-1) Multiply numerator and denominator of (9)/(z (-1)) by -1:

OpenStudy (sylph):

Sorry, the little boxes are =. What would the answer be?

OpenStudy (mathstudent55):

\(\Large \dfrac{27 x ^2 z}{ -3x ^2 z^6 } =\) \(\Large = \dfrac{27}{-3} \times \dfrac{ x ^2}{x^2}\times \dfrac{z}{ z^6 } =\) \(\Large = -9 \times 1 \times \dfrac{1}{z^5} \) \(\Large =-\dfrac{9}{z^5} = -9z^{-5}\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!