Question

what are the zeros f(x)=x^3-5x^2-6x?

Answer 1

HI!!

Answer 2

\[ f(x)=x^3-5x^2-6x\] i think you can factor this one right?

Answer 3

Hi, can u help me please? :) and yes I need help

Answer 4

each term has an \(x\) in it, "factor it out" and start with \[ x^3-5x^2-6x=0\\
x(x^2-5x-6)=0\]

Answer 5

then you have to factor \(x^2-5x-6\) do you know how to do that?

Answer 6

no ma'am

Answer 7

think of two numbers that multiplied together give \(-6\) and when you add then you get \(-5\)
since the product is negative, one of the numbers has to be positive, the other negative

Answer 8

did you get them yet?

Answer 9

one second

Answer 10

-2 * 3=-6
-6+1=-5

Answer 11

they have to be the same for both

Answer 12

like \(-2\times 3=-6\) and \(-2+3=1\) so that doesn't work
try a different pair

Answer 13

-6*1=-6
-6+1=-5

Answer 14

right

Answer 15

\[x^2-5x-6=(x-6)(x+1)\]

Answer 16

so now you have \[x(x-6)(x+1)=0\] and solve by setting each factor equal to zero

Answer 17

\[x=0\\
x-6=0\iff x=6\\
x+1=0\iff x=-1\]

Answer 18

so the zeros are 6
and -1 ?