Help pleaseeeee
The figure at right is the graph of f ′′ (x), the second derivative of a function f (x). The domain of the function f (x) is all real numbers, and the graph shows f ′′ (x) for −2.6≤ x ≤3.6. A. Find all values of x in the interval (−2.6, 3.6) where f ′(x) has a horizontal tangent. B. Find all values of x in the interval (−2.6, 3.6) where f (x) is concave upwards. Explain your answer C. Suppose it is known that in the interval (−3.6, 3.6), f (x) has critical points at x =1.37, and x = −0 .97. Classify these points as relative maxima or minima of f (x). Explain your answer.
Do you need help in this?btw I can't provide help on second part
For a given function f(x) .... f'(x) gives the slope of f(x) at every point f''(x) gives the concavity of f(x) at every point If f''(x) > 0, then f(x) is concave up and the slope is increasing ("U" shape) If f''(x) < 0, then f(x) is concave down and slope is decreasing (downward facing "U") Critical points occur at local min/max on f(x) The slope at these points is zero. Find concavity of these points by finding if f''(x) is positive or negative, this will tell you whether its a min ("U" shape) or a max( downward facing "U")
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