Question

The line that contains the point Q( 1, -2) and is parallel to the line whose equation is

y - 4 = 2/3 (x - 3)

Answer 1

What is the slope of the given line? A line parallel to the given line will have the same slope as does the given line.

Once you have this slope, use the point-slope formula to find the equation of the line with this slope and which passes thru the given point.

\[y-y _{1}=m(x-x _{1})\]

Answer 2

It doesn't give the slope of the line.

Answer 3

what mathmale was trying to say is, you need to find the slope of

y - 4 = 2/3 (x - 3)

Answer 4

any ideas now?

Answer 5

*how?

Answer 6

m= 2/3 ??

Answer 7

yes!

now, we have m = 2/3, x1 = 1 and x2 = -2

now just plug them into the equation mathmale gave you

Answer 8

y−y1=m(x−x1)

Answer 9

let me know what you get

Answer 10

kylee?

Do the best you can here with the info you have. Share your work, so that either Vocaloid or I could give you feedback on it.

Answer 11

What do I plug in for y and y1?

Answer 12

1 and -2?

Answer 13

Your new line is to pass thru the point Q(1,-2). Thus:\[x _{1}=1~and~y _{1}=2\]

Answer 14

Vocaloid: Looks like we have a conflict? Please resolve it. Thx.

Answer 15

Excuse me. x1=1 and y1=-2.

Answer 16

you're right

Answer 17

x1=1 and y1=-2.

Answer 18

;)

Answer 19

kylee: Please take this info nd finish writing the equation of this new line.

Answer 20

Does y=0 ?

Answer 21

y doesn't equal any specific value, just leave y alone and substitute the rest

Answer 22

also leave x alone

Answer 23

Kylee, you are to write an equation for a straight line here. Both x and y are VARIABLES. There is no reason to let y = 0.

Answer 24

Instead, replace x1 in the general equation with the given value, 1, and replace y1 in the general equation with the given value, -2. Show y our work, please.

Your final result MUST include the variables x and y, in a linear equation / formula.

Answer 25

y-2=2/3(x-1) ?

Answer 26

At the beginning you are given the equation of a straight line. That equation
DOES contain the value of the slope of this line. Your new line must have the same slope, because the new line is parallel to the original line.

Vocaloid gave you the correct equation to use:

\[y-y _{1}=m(x-x _{1}).\]

Answer 27

On the left side y ou 've written y-2. This is incorrect because y1 = -2, whereas your y-2 would be correct for y1=2, whereas your y1 is -2. Try again.

Answer 28

I am very confused.

Answer 29

y — ( –2 )

Answer 30

a — b = a + ( –b )

Answer 31

Yes. The left side of the general equation you're using here is \[y-y _{1}\]

Answer 32

Two examples:
1) Suppose that y1=2. What would the left side of your equation look like?
2) Suppose that y1=-2. What would the left side of your equation look like? Follow skullpatrol's advice.

Answer 33

y+2=2/3(x-1) ?

Answer 34

Good job!

Answer 35

Yes. If you'd please enclose that "2/3" in parentheses, you'd be done.

2/3(x-1) is ambiguous. Enclosing "2/3" within parentheses would remove that ambiguity.

Answer 36

^

Answer 37

Does that mean that's my answer to original question?

Answer 38

You propose a solution 3-4 minutes ago. It was OK and would have been better had you enclosed the slope 2/3 within parentheses.

Answer 39

y+2=(2/3)(x-1) ?

Answer 40

That is the correct answer.

Answer 41

Thank you for all your time and effort! Greatly appreciated everyone!

Answer 42

Thanks for trying to learn something new :-)

Answer 43

You're welcome. Thx for your perseverance.