PLEASE HELP WILL EARN MEDAL
When 27 times x squared times z all over negative 3 times x squared times z to the sixth power is completely simplified, the exponent on the variable z is _____.
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OpenStudy (briellshaw):
if you say they will earn a medal some people with give you any answer using the main words so ask for an explanation behind the answer
OpenStudy (stryder246):
here is the equation
OpenStudy (stryder246):
and ok briellshaw
OpenStudy (stryder246):
Could you please help me Mehek14
Mehek (mehek14):
What is 27/-3 = ?
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OpenStudy (stryder246):
-9
Mehek (mehek14):
Ok so -9 is the numerator
OpenStudy (stryder246):
yes
Mehek (mehek14):
\(\dfrac{x^2}{x^2}=?\)
OpenStudy (stryder246):
this is the part that i get stuck on but i think that it is x^4
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OpenStudy (stryder246):
or just x with no exponent
Mehek (mehek14):
well when we divide, you subtract the exponents
OpenStudy (stryder246):
ok so it will be x with no exponent
Mehek (mehek14):
there would be no x
Mehek (mehek14):
Now \(\dfrac{z}{z^5}\)
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OpenStudy (stryder246):
i thought that it is z/x^6
OpenStudy (stryder246):
z/z^6 my bad
OpenStudy (stryder246):
\[z/z^6\]
OpenStudy (stryder246):
are you still there
Mehek (mehek14):
Yes
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OpenStudy (stryder246):
ok wouldn't it be \[^{z^-5}\]
Mehek (mehek14):
no
OpenStudy (stryder246):
i think that the answer is -5
Mehek (mehek14):
Nope
Mehek (mehek14):
\(z=z^1\\z^5\)
Subtract the exponents
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OpenStudy (stryder246):
how did you get z^5
Mehek (mehek14):
From the question you posted?
OpenStudy (stryder246):
it says z^6
Mehek (mehek14):
Oh my bad cx
\(\dfrac{z}{z^6}\)
OpenStudy (stryder246):
its ok and 1-6=-5
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Mehek (mehek14):
it should look like
\(\dfrac{9}{z^5}\)
Your answer wants the exponent of z which is `5`
OpenStudy (stryder246):
i thought that the exponent is -5
Mehek (mehek14):
positive exponent.
OpenStudy (stryder246):
ok so the answer is 5
OpenStudy (stryder246):
Ok thanks for using you time to help me solve my problem! Thanks Again!
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