Can someone please help me to answer this math question? Please? I will fan and give a medal... Please help me to simplify this Rational Expression - 8 3 ------ - ----- x^2-4 x-2
hint: start by factoring x^2 - 4
it would be (2 + x)(-2 + x) right?
Yes. We would write that (x-2)(x+2)
To add or subtract fractions, the denominators have to be the same. So change the second fraction so that it has the same denominator.
good, then we convert both fractions to the same denominator any ideas now?
So change 8 3 ------ - ----- x^2-4 x-2 into 8 3 ------ - ----- x-2 x-2
not quite, we can't do it like that
remember, in order to keep a fraction the same, we have to change the numerator and the denominator by the same operations
to go from x - 2 to x^2 - 4, we have to multiply by (x+2)
\[\frac{8}{(x-2)(x+2)} - \frac{3}{x-2}\] \[\frac{8}{(x-2)(x+2)}-\frac{3}{(x-2)}\times \frac{x+2}{x+2}\]
so... 3 --- x - 2 becomes 3(x-2)(x+2) ------ x^2 - 4
Can you take it from there?
what do I do after that? @Mertsj
Do you see that both denominators are now the same?
yes sir
So leave the denominators alone. Use the distributive property on the numerator of the second fraction.
What did you get?
3 x^2-6 x ? @Mertsj
3(x+2)= ?????
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