Question

I need to graph a rose curve but I don't know how to move it up the y axis.

Answer 1

hmm is that a trig equation?

Answer 2

I take precalc so....

Answer 3

anyhow \(\qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{\color{purple}{ A}}({\color{blue}{ B}}x+{\color{red}{ C}})+{\color{green}{ D}}
\\ \quad \\
y=&{\color{purple}{ A}}({\color{blue}{ B}}x+{\color{red}{ C}})+{\color{green}{ D}}
\\ \quad \\
f(x)=&{\color{purple}{ A}}\sqrt{{\color{blue}{ B}}x+{\color{red}{ C}}}+{\color{green}{ D}}
\\ \quad \\
f(x)=&{\color{purple}{ A}}\mathbb{R}^{{\color{blue}{ B}}x+{\color{red}{ C}}}+{\color{green}{ D}}
\end{array}\qquad

\begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {\color{purple}{ A}}\cdot {\color{blue}{ B}}\\
\bullet \textit{ horizontal shift by }\frac{{\color{red}{ C}}}{{\color{blue}{ B}}}\\
\qquad if\ \frac{{\color{red}{ C}}}{{\color{blue}{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{\color{red}{ C}}}{{\color{blue}{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{\color{green}{ D}}\\
\qquad if\ {\color{green}{ D}}\textit{ is negative, downwards}\\
\qquad if\ {\color{green}{ D}}\textit{ is positive, upwards}
\end{array}\)


use the "vertical shift" component of it, to move it upwards

Answer 4

namely, whatever the "parent function" is, add whatever to D component, to move it upwards by that much

Answer 5

Well I have this equation: \[r=3\sin 3.99\theta \]

Answer 6

And I want to move it up the y axis by 5.

Answer 7

\(\Large r=3\sin 3.99\theta+{\color{green}{ D}}\)

Answer 8

No, it does not move it up the y axis.

Answer 9

It only makes the graph bigger.

Answer 10

hmmm

Answer 11

hmm you're right... hmmm they do not apply to polars :(

Answer 12

:/

Answer 13

I see a lot of rotations at http://www.ck12.org/trigonometry/Transformations-of-Polar-Graphs/lesson/Transformations-of-Polar-Graphs-TRIG/?referrer=concept_details

but not much on moving it on either side :/

dunno on that one

Answer 14

Okay, thanks for trying to help though

Answer 15

Hi

Answer 16

hi ganeshie :)