Question

I need help I don't get how to make equations

Answer 1

Here

Answer 2

familiar with this formula ? \[M_{a}V_{a} = M_{b}V_{b}\]

Answer 3

no

Answer 4

so M means molarity, in moles/L
and V means the volume in L

what do you think a and b stand for?

Answer 5

oh i think i rememnber

Answer 6

i dont know wat a and b is tho

Answer 7

a = acid b = base

Answer 8

so the molarity of the acid times the volume of acid = molarity of base times the volume of the base.

Answer 9

yeah but i need to make the equation which i don't know how to

Answer 10

let's start with understanding this equation first

Answer 11

okay

Answer 12

so now what does this mean to you

\[M_{a}V_{a} = M_{b}V_{b}\]

Answer 13

molarity=moles/liters

Answer 14

so what this formula means is this

Answer 15

this is the definition of neutralization reaction

\[\frac{ moles }{ L }*L = \frac{ moles }{ L } * L ~ moles_{acid} = moles_{base}\]

Answer 16

okay

Answer 17

this means that the number of moles of acid = number of moles of base at neutralization.

Answer 18

okay so what do we do next

Answer 19

alright now let's balance the reaction

Answer 20

\[2CH_{3}COOH + Ba(OH)_{2} \rightarrow 2H_{2}O+ Ba(CH_{3}COO)_{2}\]

Answer 21

50 mL of 0.55M barium hydroxide

and

75 ml of acetic acid.

let's go back to our balanced equation. we need the number of moles of barium hydroxide first.

Answer 22

okay

Answer 23

\[\frac{ 50 }{ 1000 }L~Ba(OH)_{2}*(\frac{ 0.55moles }{ L }) = 0.0275~moles~Ba(OH)_{2}\]

Answer 24

how did u get the 1000ml

Answer 25

\[\frac{ 2*CH_{3}COOH }{ Ba(OH)_{2} } *(0.0275~moles~Ba(OH)_{2}) = 0.055~Moles~CH_{3}COOH\]

Answer 26

\[\frac{ 0.055~Moles~CH3COOH }{ 0.075~L } = 0.73~M\]

Answer 27

@sweetburger I thought about using the molarity formula but I was thinking of taking into account the fact that we don't have a 1:1 molar ratio.

Answer 28

@MarcoReus11 so what I did was I balanced the equation first and then figured out the number of moles of CH3COOH that reacted by using the molar ratio.

Answer 29

just to get up to speed are you guys working on question 6?

Answer 30

would u find the moles of barium hydroxide than convert it to moles in acidic acid? than set up the equation and find molarity?

Answer 31

that's exactly what I did

Answer 32

Like you can't just use MaVa = MbVb Because you don't have a 1:1 molar ratio

Answer 33

i know how to do the m=moles/liters i just dont know how to make the equation

Answer 34

@MarcoReus11 so you had to balance the equation first

Answer 35

that's the first step

Answer 36

yeah thats what i mean by

Answer 37

@Photon336 beautiful work i would have done it the same way.

Answer 38

thanks a-lot @sweetburger I needed a second opinion b.c first I used MaVa = MbVb but that had to be wrong lol

Answer 39

thank you @Photon336 i try and do the other myself i will tag u when i am done