@YanaSidlinskiy
29=33+a*2.5
Ok, so I don't know if you have read the theoretical part. But I'll like to discuss few basic things first before we solve this question. Ok?
Do you understand acceleration/deacceleration ?
Acceleration is when the rate inscreases and deacceleration is when spead decreases
Yes, there are two types of motion. One in which the body keeps moving with a constant velocity. Like if its initial velocity is 33 m/s then it will keep moving with this same velocity. The other is accelerated motion in which its velocity will keep increasing at a certain rate.
Cool?
Ok
Now, while solving numerical problems. You just need to keep in mind these 3 equations. 1) V=U+at 2) \(\sf S=Ut + 1/2at^2\) 3) \(V^2=U^2+2as\) Where, V=final velocity U=Initial Velocity a=acceleration t=time
and S=distance traveled.
These are popularly called as Equations of motion. Cool?
Yes
Ok, let's start solving the easy pisy question. Read your original question and note down what information is given first.
Initial velocity=? Final velocity=? acceleration=? time=? distance=?
Can I go shower lol
You can wait for 10 mins. That's what this would take.
Ok ok fine..
I'm sick of this problem.
IV= 33 FV = 29 A= NOT GIVEN Time=2.5 Distance= Idk
Yes, that's right! You need to find the distance.
Now see which equation from the above can you use to find S?
2nd
There are two equations which has S in it.
You can use either 2nd or 3rd. Right?
I think so..
But see, you can't use then directly because both of them requires info about acceleration and we don't have it. Correct?
Yes
So, we will have to use the 1st equation to find a and then substitute its value in either 2nd or 3rd equation to get the value of S
But, I gave you an easy way. \(\sf v=u+at \\ (v-u)/t = a ...... (1)\) Substituting this value of a in 2nd equation of motion \(\sf S=ut+1/2 \frac{v-u}{t} \times t^2\\ S=\frac{v+u}2{} \times t\)
Simply put the values in the last equation and you will get the answer.
WTF is U and
U=initial velocity V=final velocity S=distance traveled t=time a=acceleration
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