Help, I'll fan and medal Find f(x) and g(x) so that the function can be described as y = f(g(x)). y = Four divided by x squared. + 9
Answers: f(x) = x + 9, g(x) = Four divided by x squared. f(x) = x, g(x) = Four divided by x. + 9 f(x) = One divided by x., g(x) = Four divided by x. + 9 f(x) = Four divided by x squared., g(x) = 9
Could you use the equation tool to write the question and answers? That way confusion can be prevented
Can you help? @Vocaloid I only have one more question after this one and I'll give you medals for both questions
\[A. f(x)=x+9, g(x)=4/x^2\]
\[B. f(x)=x g(x)=4/x +9\]
\[C. f(x)=1/x g(x)= 4/x+9\]
\[D. f(x)=4/x^{2} g(x)=9\]
basically, you want to write the function where g(x) can be inserted as x into f(x)
And \[y = \frac{ 4 }{ x^ {2} }+9\]?
I did that, but I'm still super confused
For example, in letter D, you would substitute 9^2 for x^2. We can cancel out D since it would equal 4/81. Does this make sense?
I think so
Yes, so then answer choice D is wrong?
D is incorrect.
Now let's look at A. Can you figure out whether it is right or wrong?
I think it's wrong
Substitute 4/x^2 into the f(x) equation. What do you get?
Ugh..I'm not sure, how do I figure it out again?
You plug in the value of the g(x) equation into the equation of f(x). For example, f(x)=1 + x and g(x)=4 If we were to simplify this, we would get 5 since we would substitute the g(x) value (a.k.a four) into the equation on the left.
So for A it would be 9/4?
\[A.f(x)=x+9, g(x)=4/x^ {2} \] Let's plug in g(x) into the first equation \[f(x)=g(x)+9\] \[f(x)=\frac{ 4 }{ x^ {2} }+9\]
Does that make sense?
I think so
Yes, it does
@Aveline ??
...we've got the answer, don't we?
Yes, if I open a new question, can you help with my last one and I'll give you another medal? You're a life saver.
I just need you to check my answer
I'm sorry, but I'm in computer class right now and it ends in 3 minutes >-< I'd love to help but I'm sure someone else will be willing to help you too :)
Okay, thanks anyways
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