Question

I've been stuck on this question for too long, I just don't understand it :/

3x+y+4=9x

Answer 1

if we subtract \(9x\) from both sides, we get:
\[3x + y + 4 - 9x = 9x - 9x\]
and after a simplification we get:
\[ - 6x + y + 4 = 0\]
which is the equation of a line in the cartesian plane \((x,y)\)

Answer 2

Do I then plug in numbers for x and y?

Answer 3

yes!
If we substitute \(x=0\), then we get:
\[ - 6 \cdot 0 + y + 4 = 0 \Rightarrow y = - 4\]
so the line passes at point:
\[{P_1} = \left( {0, - 4} \right)\]
now, please substitute \(y=0\) nd then find \(x\)

Answer 4

and*

Answer 5

However - since there are 2 unknowns and 1 equation you cannot 'solve' this with numbers
the equation above is the best you can do, unless you are told more in the question

Answer 6

So it would be -6x + 0 = 0 and you'd divide -6 on both sides so x would equal 0?

Answer 7

The question's instructions are "Simplify the equation if possible. Then graph the equation by any appropriate method."

Answer 8

after the substitution, we can write:
\[ - 6x + 0 + 4 = 0 \Rightarrow 6x = - 4\]
@srslyjocelyn

Answer 9

OK

−6x+y+4=0

is the same as
y = 6x -4

this is a straight line - you should be able to tell me the slope and intercept of the line and therefore graph it...

Answer 10

next I divide both sides by \(6\) so I can write this:
\[\frac{{6x}}{6} = \frac{{ - 4}}{6}\]
please simplify @srslyjocelyn

Answer 11

x=-.6?

Answer 12

more precisely, we have:
\[x = - \frac{2}{3}\]
so the line passes at point
\[{P_2} = \left( { - \frac{2}{3},0} \right)\]

Answer 13

do you recognise
y=mx +b

as the form of a straight line?

Answer 14

if ytou want to draw such line, it is suffice to draw both points:
\[{P_1} = \left( {0, - 4} \right),{P_2} = \left( { - \frac{2}{3},0} \right)\]
and then an infinite line through such points

Answer 15

Even more confused now wow... The issue is I honestly don't understand how I'd graph 2/3 or anything along those lines when the graph provided only allows whole number.

Answer 16

here is my drawing: