Question

Determine the number of grams of Potassium Iodate present in 11.1 g of a 0.221 m (molality) Potassium Iodate solution.

Answer 1

So far this is what I have tried.

11.1g *1kg/1000g = 0.0111 kg

0.221 moles/kg *0.0111kg = 0.0024531 moles
0.0024531 moles * 214g/mole = 0.5249634. It is saying that my answer is incorrect

Answer 2

sig figs maybe?

Answer 3

@Vocaloid I used 0.525 as my answer and it told me that i was incorrect by less than 10%