When taking the inverse of a matrix, does the matrix have to be a square matrix in order for it to be invertible?
Yes the matrix A must be square so that you can compute \[\Large A*A^{-1}\] and \[\Large A^{-1}*A\] which both will lead to the identity matrix \(\LARGE I\)
this is assuming that the inverse exists
So the reason why it has to be square is so that it is commutative? Following the rule AA^-1 = I = A^-1A
https://people.richland.edu/james/lecture/m116/matrices/inverses.html snapshot of the page http://prntscr.com/bdq652
Is it possible in any situation at all, to take the inverse of a matrix that is not square?
Let's assume matrix A wasn't square. Let's say matrix A has the dimensions 3x5, so matrix A has 3 rows and 5 columns Let matrix A be invertible and let's assume matrix B is the inverse of matrix A so that means A*B = I B*A = I But we have a problem A*B is NOT defined if matrix B was of the size 3x5, or 5x3 or even 3x3. If B was 5x5 then it would work BUT it would not work with B*A. So to make all the dimensions match up, we need A and B to both be square matrices. We need them to have the same number of rows and columns.
http://people.revoledu.com/kardi/tutorial/LinearAlgebra/MatrixGeneralizedInverse.html snapshot http://prntscr.com/bdq7db that is basically saying technically it is possible, but it's not a full inverse. It would be "half" an inverse so to speak. Either a left-inverse or right-inverse
Can you find out determinant of a matrix which is not square?
No, in order to take determinant of a matrix, the matrix must be square.
You gave the ans yourself... When we can't evaluate the determinant then we don't talk about the inverse of the matrix
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