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Mathematics 7 Online
OpenStudy (anj123):

When taking the inverse of a matrix, does the matrix have to be a square matrix in order for it to be invertible?

jimthompson5910 (jim_thompson5910):

Yes the matrix A must be square so that you can compute \[\Large A*A^{-1}\] and \[\Large A^{-1}*A\] which both will lead to the identity matrix \(\LARGE I\)

jimthompson5910 (jim_thompson5910):

this is assuming that the inverse exists

OpenStudy (anj123):

So the reason why it has to be square is so that it is commutative? Following the rule AA^-1 = I = A^-1A

jimthompson5910 (jim_thompson5910):

https://people.richland.edu/james/lecture/m116/matrices/inverses.html snapshot of the page http://prntscr.com/bdq652

OpenStudy (anj123):

Is it possible in any situation at all, to take the inverse of a matrix that is not square?

jimthompson5910 (jim_thompson5910):

Let's assume matrix A wasn't square. Let's say matrix A has the dimensions 3x5, so matrix A has 3 rows and 5 columns Let matrix A be invertible and let's assume matrix B is the inverse of matrix A so that means A*B = I B*A = I But we have a problem A*B is NOT defined if matrix B was of the size 3x5, or 5x3 or even 3x3. If B was 5x5 then it would work BUT it would not work with B*A. So to make all the dimensions match up, we need A and B to both be square matrices. We need them to have the same number of rows and columns.

jimthompson5910 (jim_thompson5910):

http://people.revoledu.com/kardi/tutorial/LinearAlgebra/MatrixGeneralizedInverse.html snapshot http://prntscr.com/bdq7db that is basically saying technically it is possible, but it's not a full inverse. It would be "half" an inverse so to speak. Either a left-inverse or right-inverse

OpenStudy (samigupta8):

Can you find out determinant of a matrix which is not square?

OpenStudy (anj123):

No, in order to take determinant of a matrix, the matrix must be square.

OpenStudy (samigupta8):

You gave the ans yourself... When we can't evaluate the determinant then we don't talk about the inverse of the matrix

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