Question

When 27 times x squared times z all over negative 3 times x squared times z to the sixth power is completely simplified, the exponent on the variable z is _____.

Answer 1

i need help really bad, i think it is 3 but im not sure

Answer 2

Post a screenshot or use the equation editor.

Answer 3

27x^2z/-3x^2z^6

Answer 4

thats the equation @agent0smith

Answer 5

You gotta learn to use the equation editor... is it this \[\large \frac{ 27x^2z}{ -3x^2z^6 }\]

Answer 6

yes

Answer 7

So just simplify everything using exponent rules

Answer 8

i did and got three
is that right?

Answer 9

Show work cos i have no idea what you mean by just "three"

Answer 10

z's exponent is 3

Answer 11

Just show your whole work on the simplification, and it def isn't 3

Answer 12

oh

Answer 13

\[\Large \frac{ x^a }{x^b } = x^{a-b}\]

Answer 14

27×x2×z−3×x2×z4⇒−9×x2×z−3×x2×z3⇒−9z3⇒−9z−3

Answer 15

thats what i got....

Answer 16

I can't follow that... time to start practicing the equation editor.

Answer 17

im probably completely wrong

Answer 18

can you help me solve it

Answer 19

please

Answer 20

large \frac{ 27x^2z}{ -3x^2z^6 }

copy and paste that into the equation editor and start simplifying it. I don't understand how you got an exponent of 3 on the z.

Answer 21

im trying but it wont do anyhing

Answer 22

is there a possibility that it could be five?

Answer 23

\[\large \frac{ 27x^2z}{ -3x^2z^6 }\] \[\large \frac{ -9x^2z}{ x^2z^6 }\] \[\large \frac{ -9z}{ z^6 }\]

This is the correct step by step working so far. I can not follow yours, in your working, the exponent on the z seems to change randomly for no reason?

Answer 24

im probably doing it wrong

Answer 25

Well you need to start using the equation editor so people can follow your work, the way you wrote it is not easy to follow

Answer 26

im sorry

Answer 27

Now simplify the last step, using the exponent rule i posted earlier.

Answer 28

would it be -3

Answer 29

Tell me exponent on the z on the top of the fraction.

Answer 30

Or tell me why you think it's -3?

Answer 31

because you add the 6 to the -9

Answer 32

im completely wrong arent i?

Answer 33

The -9 has absolutely nothing to do with the z's btw. It being there makes no difference.

Answer 34

\[\large \frac{ -9z^1}{ z^6 }\]use the exponent rule, remembering that the z on top has an exponent of 1. The -9 has no effect at all, ignore it.

Answer 35

oh okay ...

Answer 36

so we subtract 1 and six

Answer 37

soo it would be five?

Answer 38

i mean 6 and one

Answer 39

sorry

Answer 40

do you think \[\large \frac{ -9z^1}{ z^6 } \] becomes \[\large -9z^5\] or \[\large \frac{ -9}{ z^5 }\] which do you think is correct?

Answer 41

the first one? @agent0smith

Answer 42

im sorry i was on the phone with a teacher, @agent0smith

Answer 43

Good Ol'dba. Did good did ya?

Answer 44

you know if u had an example for this formula it would be much much easier.

Answer 45

im sorry
can someone just tell me the answer?

Answer 46

5

Answer 47

are you sure?

Answer 48

If you rewrite it and take the z out of the denominator it would be -5

Answer 49

so -5

Answer 50

\[\large \frac{ -9z^1}{ z^6 }\]simplifies to \[\large -9z^{-5}\] since 1-6 is -5. But you shouldn't finish a problem with negative exponents, and hopefully you remember that you can move a negative exponent into the denominator to make it positive, so \[\large \frac{ -9}{ z^5 }\]

Answer 51

so 5

Answer 52

^ what he said. The answer is not -5 though.\[\frac{ 9z }{ z^6 } = \frac{ 9 }{ z^5 } = 9z ^{-5}\]

Answer 53

it is 5 thank you @agent0smith