Question

@zeronknight

Answer 1

What I am going to be showing you will show you how to solve:

What number is 20% of 80?
The number 12 is what percent of 68?

and

The number 25 is 25% of what number?

You will learn how to solve these by using this basic proportion set up shown below

\(\dfrac{x}{y} = \dfrac{p}{100}\)

Answer 2

Sorry that took so long.
Which one would you like to solve first? If you are still up for this

Answer 3

Hmm The second one

Answer 4

i'll try to do 1

Answer 5

i think 1 is 16

Answer 6

@leenathan I am sory, but this is for Zeron. If you want to watch you can :)
Ok, so first let me tell you what x equals, y equals, and p equals.

x = the partial number
y = the whole number given in the problem
p = the percent given in the problem

Let's take a look at the second problem, 'The number 12 is what percent of 68?'

Answer 7

oh sorry

Answer 8

Do you know what I mean when I say partial number and whole number?

Answer 9

Not exactly. Partial is like 0.75% of a whole number?
Whole number is like 1?

Answer 10

The partial and whole number won't be a percent. If we look at the problem,

The number 12 is what percent of 68?

Our partial number is 12 and our whole number is 68, because we are trying to find the percentage of \(\dfrac{12}{68}\)

Answer 11

OH

Answer 12

The partial number is the numerator, and the whole number is the denominator. In most cases, the whole number will be more than the partial number

Answer 13

Do you understand? Heheh :)

Answer 14

Yes.

Answer 15

The partial number is just a partial of the whole number/denominator that is 68

Answer 16

Usually the numerator, and in most cases, lower than the whole number? XD

Answer 17

remember you can always replace % with 1/100

Answer 18

That is one way to put it.

So now we need to place the partial, 12, and the whole, 68, into our proportion \(\dfrac{x}{y} = \dfrac{p}{100}\)

\(\dfrac{12}{68} = \dfrac{p}{100}\)

Answer 19

p/100 = p%

Answer 20

And to solve, you cross multiply and divide.

(I should've chose different numbers)

Anyways, you need to round to the nearest tenth, or whatever is stated in the question.

Answer 21

percent means per 100

Answer 22

12 x 100
1200 / 68 = p?

Answer 23

Yes

Answer 24

And our 'p' will equal approximately 17.65 or 17.7

Answer 25

17.6*

Answer 26

Do you understand all of this?

Answer 27

Yes.

Answer 28

Just to make sure

Answer 29

Let me write a summary XD

Answer 30

OK, you can do that if you want

Answer 31

X = partial Y = Whole P = The percentage we want.
We replace X with 12
And Y with 68
Then we cross multiply. 12 x 100, and divide 1200 by 68. And then we get our percentage.

Answer 32

Yes :) That is for the second question.

Would you like to do any of the other questions, or do you feel like you understand?

Answer 33

Would the first question be different?

Answer 34

Like on how to solve it?

Answer 35

All of the questions are different. Either the partial is missing, the whole, or the percent.

Answer 36

Ok, can we do the first?

Answer 37

Yes. Are you able to identify the partial, whole, and percent?

Whichever one you can't identify is what we are trying to solve for

Answer 38

We can't identify the partial.

Answer 39

Correct, so are you able to plug in the information and solve?

Answer 40

Not exactly. Are we supposed to divide 80 by 20%?

Answer 41

We replace the P with 20% and the W with 80 right?

Answer 42

Let's plug in the values into the proportion.\(\dfrac{x}{y} = \dfrac{p}{100}\)

\(\dfrac{x}{80} = \dfrac{20}{100}\)

Answer 43

Yes

Answer 44

so 80 x 20 / 100?

Answer 45

80 x 20 = 1600 / 100 = 16? lol

Answer 46

Yes, so x = 16.

Answer 47

\(\dfrac{16}{80} = \dfrac{20}{100}\)

\(0.2 = 0.2\)

Answer 48

0.2? What's that for

Answer 49

If you want to check the answer is right, divide 16 by 80, and 20 by 100. If the answer is equal, then you have done everything right.

Answer 50

Oh

Answer 51

For the third one, that would be 100 right?

Answer 52

Yes :)

Answer 53

You did great!

Answer 54

Thank you for your help! I really appreciate it :)

Answer 55

No problem. If you need any help like this again, I am glad to do so