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Mathematics 14 Online
OpenStudy (errinss):

help!! will fan and medal

OpenStudy (errinss):

OpenStudy (agent0smith):

First do prime factorization on 72 (what numbers multiply to give you 72?)

OpenStudy (errinss):

9*8

OpenStudy (agent0smith):

Keep going, until the numbers are as small as possible

OpenStudy (errinss):

i dont get it

OpenStudy (agent0smith):

What numbers multiply to give you 9, and 8.

OpenStudy (errinss):

3*3 and 4*2

OpenStudy (agent0smith):

Keep going...

OpenStudy (errinss):

3*3 and 2*2*2

OpenStudy (agent0smith):

Good, now put it all together.

OpenStudy (errinss):

huh

OpenStudy (agent0smith):

72 is the same as...

OpenStudy (errinss):

idk.... A?

OpenStudy (agent0smith):

No, you broke up 72 into the smallest possible factors. 3*3 and 2*2*2 ^ put them all together as one product, and also write it using exponents.

OpenStudy (errinss):

how?

OpenStudy (agent0smith):

Eg. 5*5 is the same as 5^2, right? 7*7*7 is 7^3, right? Do that, with what you have.

OpenStudy (errinss):

3^2 2^3

OpenStudy (agent0smith):

Now don't forget that it's all under a cube root sign. \[\Large \sqrt[3]{3^2 * 2^3}\] Now you can try simplifying.

OpenStudy (errinss):

ugh holy crap ow do i do that

OpenStudy (errinss):

how*

OpenStudy (agent0smith):

Here's an example\[\Large \sqrt[3]{7^3} = 7\]and another \[\Large \sqrt[3]{5*11^3}=11\sqrt[3]{5}\]notice since the 11 is cubed, you can take it out of the cube root.

OpenStudy (errinss):

so C?

OpenStudy (agent0smith):

\[\Large \sqrt[3]{3^2 * 2^3} = 2\sqrt[3]{3^2 }\]

OpenStudy (errinss):

thats not an option

OpenStudy (agent0smith):

Ugh.

OpenStudy (agent0smith):

I'm sure you can simplify what I gave.

OpenStudy (errinss):

i tried and you ignored it... i asked if it was C

OpenStudy (agent0smith):

Because I want you to be 100% sure of the answer. You shouldn't need confirmation. Just simplify what I gave.

OpenStudy (errinss):

*growls playfully* do i have to?

OpenStudy (agent0smith):

Plus I gave you a medal for a reason lol

OpenStudy (errinss):

\[2\sqrt[3]{9}\]

OpenStudy (errinss):

I WAS RIGHT, right?

OpenStudy (agent0smith):

Much better. I don't care if whatever letter you gave is correct. Show me that you know the correct answer, like you just did.

OpenStudy (errinss):

lol wow ok....thx

OpenStudy (errinss):

X'D lol now i cant stop laughing

OpenStudy (agent0smith):

lol well people like to throw out guesses like "is it B?" and just hope someone will give them the answer. Show you know the correct answer.

OpenStudy (errinss):

can you help me with another? lol

OpenStudy (agent0smith):

Sure. But if it's like this, you better have learned something ;)

OpenStudy (errinss):

its like this and i'll show my work.... lol

OpenStudy (errinss):

OpenStudy (errinss):

so 9*6 goes into 56 now if i simplify i get 3*3 and 3*2

OpenStudy (errinss):

3^2 and 3*2 uhm...now im lost....

OpenStudy (agent0smith):

Maybe check your times tables :P

OpenStudy (errinss):

oops duh lol

OpenStudy (agent0smith):

And don't use "and" show things correctly... if they're multiplied together, then show it (it will help you)

OpenStudy (errinss):

28*2

OpenStudy (agent0smith):

"3^2 and 3*2" don't use "and" here i mean. If they're multiplied together, show it.

OpenStudy (errinss):

7*8, 14*4,

OpenStudy (agent0smith):

It doesn't matter what numbers you use. Just get them as small as possible, just like you did in the first problem.

OpenStudy (errinss):

7*2 2*2

OpenStudy (agent0smith):

Why is there a blank space in the middle?

OpenStudy (errinss):

\[\sqrt[3]{7*2*}2^{2}\]

OpenStudy (errinss):

i think...am i doing this right?

OpenStudy (agent0smith):

You are on the right track.

OpenStudy (errinss):

\[2\sqrt[3]{7*2}\]

OpenStudy (agent0smith):

Go back a step. First show me 56 written with the smallest possible factors

OpenStudy (errinss):

7*2*2^2

OpenStudy (agent0smith):

Right but that isn't the way I'd write it... look at how you did the first problem.

OpenStudy (agent0smith):

Mainly, why do you have a 2*2^2 in there? Isn't there a better way to write that?

OpenStudy (errinss):

\[\sqrt[3]{7*2^{3}}\]

OpenStudy (agent0smith):

much better.

OpenStudy (errinss):

\[2\sqrt[3]{7}\]

OpenStudy (agent0smith):

\[\Large \checkmark \]

OpenStudy (errinss):

*hugs you* THANKS!!!!

OpenStudy (agent0smith):

you're welcome *awkwardly hugs back*

OpenStudy (errinss):

1 more? heh sorry i like hugs...im weird

OpenStudy (agent0smith):

Hugs are nice. I'd probably hug you back not-awkwardly Sure. But make sure to use everything you've done so far.

OpenStudy (errinss):

OpenStudy (errinss):

this one is negative so it kinda threw me off a lil

OpenStudy (agent0smith):

-81 = -1*81 And the cube root of -1 is just -1, so you can pull the negative out of the square root and continue

OpenStudy (errinss):

\[\sqrt[3]{3^4}\]

OpenStudy (agent0smith):

The negative can't just disappear. And remember that you can only take things that have an exponent of 3, out of the cube root

OpenStudy (errinss):

ik i wasnt.......lol i forgot the negative\[\sqrt[3]{-3^3*3}\]

OpenStudy (agent0smith):

There you go.

OpenStudy (errinss):

\[-3\sqrt[3]{3}\]

OpenStudy (agent0smith):

\[\Large \checkmark\]

OpenStudy (errinss):

woohoo XP

OpenStudy (errinss):

i think i got this...sorta

OpenStudy (agent0smith):

You seem to for the most part

OpenStudy (errinss):

*hugs u again* THX FOR THE HELP XP

OpenStudy (agent0smith):

*hugs*

OpenStudy (errinss):

can you help me with applications of cylinders?

OpenStudy (errinss):

im gonna close this question and open a new one tho

OpenStudy (agent0smith):

Probably

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