Probability question
How many times must you roll a four sided die so that the probability of getting at least 3 twos is 0.3214?
You have studied bernoulli trials.
@samigupta8 Is that similar to binomial theorum?
Yeah!
In this , we have n trials out of which we represent p- success and q-failure. Then we write accordingly
Ohh, cool @samigupta8 What would p and q be in this case though, the probability of getting a 2 and not gettinga 2?
I am impressed!
@samigupta8 but then how do we solve if we don't know n?
We can !
How? o:
Can you write the numerical representation of the problem? With the help of info,i gave you.
\[p(n)=C(n,r) \times (1/6)^r \times (5/6)^{n-r}\]
Is that it?
Don't you think that it should be (5/6)^r and (1/6)^(n-r)?
Aren't we looking for at least 3 times its 2, so we use r as the number of times we get 2, a chance of 1/6? I think im not understanding something :(
First of all, i should tell you that we start by writing it as nCr (p)^(n-r) (q)^r
r is the number of times we need to get the desired result.
Yup :) is p = 1/6?
Yo
Four sided dice is not a six sided dice. Isn't it?
OHHHHH YEAH So r=1/4?
No
It's the value of p
And i told you what is r.
@ahsome are you getting it?
SORRY, i was tryign to do it myself. So p = 1/4 right?
Yeah.
But how do you know r?
It's given that at least 3 times. So we have to do it like subtract the probability of 0,1, and 2 success from 1
You here!
OHH, I see. Doesm't that just give you the probability, and not the amount needed? Don't they give aprobability of 0.3124?
Yeah! That's how you can get value for n .
Ohh, OK So we know that p=1/4, q = 3/4, r = 0, 1, and 2. Now we just find n?
Yeah.
How do we find n?
1- all the probability upto no. of success 2 .
Would return after about 3 hours. A bit sleepy. Sorry!
OK then :) See ya @samigupta8 I am not sure the equation to find n, but ill try to do it
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