Question

Help me with this

Answer 1

When quadrilateral ABCD is translated to A'B'C'D', we need to know the original coordinates, and the transformation.
Original coordinates (you should be able to recognize the following by reading graphs):
A(2,-1),
B(1,-4)
C(3,-5)
D(5,-3)
The transformation requested is 3 units down, and 4 units left.
In the Cartesian plane, positive x direction is to the right, and positive y direction is up.
So 3 units down (negative y) and 4 units left make a translation vector of (-4,-3).
The translation T(a,b) is defined as translating points a units \(right\) and b units \(up\).
So our problem becomes T(-4,-3).
The translation transformation is defined as
T(a,b): (x,y)->(x+a, y+b)
which means that the point (x,y) would become (x+a, y+b).
Since our translation vector is (-4,-3), we have a=-4, b=-3.
So to translate point A(2,-1)->A'(2-4,-1-3)=A'(-2,-4).
You can complete the quadrilateral A'B'C'D' similarly.

Answer 2

WAit I dont get it

Answer 3

Please start reading from the beginning. What do you not get?