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Mathematics 13 Online
OpenStudy (xbx1sour_diesel):

need answered fast :( if cos(53)=0.6 what is some of its complement

jhonyy9 (jhonyy9):

do you know what mean complementray angles ?

OpenStudy (xbx1sour_diesel):

sine*

OpenStudy (xbx1sour_diesel):

not some

jhonyy9 (jhonyy9):

complementry angles are two angles what sum is equal 90 degree ok. ?

OpenStudy (xbx1sour_diesel):

uh? idk anything about triangles

jhonyy9 (jhonyy9):

so in this above case than you know that cos 53 decgree is equal 0,6 this mean that this is an angle of 53 degree - yes ?

jhonyy9 (jhonyy9):

from 53 till 90 how many degree are there ?

OpenStudy (xbx1sour_diesel):

37

jhonyy9 (jhonyy9):

yes exactly

OpenStudy (xbx1sour_diesel):

okay so what do i put?

jhonyy9 (jhonyy9):

so cos 53 = 0,6 than cos 37 = ?

OpenStudy (mrnood):

the cos of an angle is always equal to the sin of its complement cos x = sin (90-x)

OpenStudy (xbx1sour_diesel):

what is x?

OpenStudy (mrnood):

x is ANY angle

jhonyy9 (jhonyy9):

@AmTran_Bus tag me there please

OpenStudy (xbx1sour_diesel):

so my answer is cos x = sin (90-x)

OpenStudy (xbx1sour_diesel):

?

OpenStudy (mrnood):

no - the question asks you fro the sin of the complemetn of 56 BUT the cos of an angle is always equal to the sin of its complement AND the sin of an angle is always equal to the cos of its complement therefore you can think about what you know - and my statements - you can then easily find the answer

OpenStudy (xbx1sour_diesel):

okay so what would the answer be because i cant afford to get this wrong

OpenStudy (mrnood):

if you can't afford to get it wrong then study the information you are given. There is only one simple step you need to take from the above: the cos of an angle is always equal to the sin of its complement hence the cos of 56 is always equal to the sin of its complement

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