Can someone check my answer, I'll fan and medal Determine algebraically whether the function is even, odd, or neither even nor odd. f as a function of x is equal to x plus quantity 12 over x
I said odd
So what is your answer?
I messed up in that equation!
i think you have made a typo.. in your first post
The equation is \[f(x)=x+\frac{ 12 }{ x }\]
Do you know what is the condition for a function to be odd?
It depends on the exponents, right? That's what my teacher told me @priyar
Actually there is a small condition that you can check to decide about this. If f(-x)=f(x) then even funct. If f(-x)= -f(x) then odd funct.
Now can you tell me ?
Is it an even function?
@priyar
Did you check the condition? Can your show your steps?
I'm confused..
It is actually simple. Let me show you an example.. if i am given f(x) = 3x i will check for f(-x), here all i need to do is replace "x" with "-x" so what will be f(-x)?
It would make it odd
Good!! now do the same for our Q
@babtaooche ?
Would it be odd?
Good job!
Thank you!
Now you know how to solve such Q's right?
Yes!
Great! you deserve a medal
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