Mathematics
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OpenStudy (kimberly_pr):
Need help!! Will medal and fan!!
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OpenStudy (kimberly_pr):
The graph of the sine curve below is of electromagnetic energy that represents red light:
OpenStudy (kimberly_pr):
What function accurately represents the sine curve for red light?
OpenStudy (kimberly_pr):
And I have the answer choices:
f(x) = sin pi over 640x
f(x) = sin 640πx
f(x) = sin 320πx
f(x) = sin pi over 320x
OpenStudy (kimberly_pr):
Hey @Mehek14 can you help please?
OpenStudy (kimberly_pr):
Or @fairytail_lover
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OpenStudy (kimberly_pr):
Or @nincompoop
@jigglypuff314
@mayankdevnani
@Preetha
OpenStudy (kimberly_pr):
Or @agent0smith
@welshfella
OpenStudy (kimberly_pr):
Or @ILovePuppiesLol
@just_one_last_goodbye
@sammixboo
OpenStudy (kimberly_pr):
Hey @agent0smith do you know how to do this?
OpenStudy (agent0smith):
First. Find the period from the graph
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OpenStudy (agent0smith):
Then your function will be sin(bx)
where \[\large period = \frac{ 2\pi }{ b}\] solve for b
OpenStudy (kimberly_pr):
Is the answer sin320 pi x
(answer choice C)
OpenStudy (kimberly_pr):
Wait no, I think that's wrong :/ I'm confused
OpenStudy (kimberly_pr):
The period is 640, so 640= 2pi/b ... And then where do I go from there?
OpenStudy (agent0smith):
Well, you need b, so... :P
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OpenStudy (agent0smith):
And I don't care what the answer choice is, just work out the correct function first
OpenStudy (kimberly_pr):
But what would the b be? It doesn't say anything about the b?
OpenStudy (agent0smith):
Solve for b. You have the equation for it above
OpenStudy (kimberly_pr):
I got about 4,021 :/
OpenStudy (agent0smith):
640= 2pi/b solve for b. Keep everything exact, ie leave pi as pi.
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OpenStudy (kimberly_pr):
OHH, ok. Sooo 1,280 pi = b
OpenStudy (agent0smith):
No...
OpenStudy (welshfella):
first cross multiply
640b = 2 pi
now what is b?
OpenStudy (agent0smith):
\[\large 640= \frac{ 2\pi }{ b}\]multiply both sides by b
OpenStudy (kimberly_pr):
Ok so 640b = 2 pi
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OpenStudy (kimberly_pr):
What do I do next? Divide by 2?
OpenStudy (agent0smith):
You want to get b alone... so divide both sides by 640
OpenStudy (kimberly_pr):
Ohh, ok so b = 2 pi/ 640
OpenStudy (kimberly_pr):
But that's not an answer choice... what do I have to do next?
OpenStudy (kimberly_pr):
Oh wait, now that I have b I can plug it in the formula right?
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OpenStudy (kimberly_pr):
So 640 = 2 pi/ (2 pi/ 640) ???
OpenStudy (agent0smith):
^nooooo
"Ohh, ok so b = 2 pi/ 640"
Simplify that first.
Then plug into sin(bx)
OpenStudy (welshfella):
you can simplify 2 pi/640
divide top and bottom by 2.
OpenStudy (kimberly_pr):
Ok so pi/ 320
OpenStudy (kimberly_pr):
And now I have to do sin (pi/320) ?
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OpenStudy (kimberly_pr):
I got 0.000171347
OpenStudy (kimberly_pr):
?
OpenStudy (agent0smith):
Noooooooo
"Then plug into sin(bx)"
You forgot the x.
OpenStudy (welshfella):
theres no need to work out pi/320
just leave it like that
OpenStudy (kimberly_pr):
Ohhh, so is the answer D?
f(x) = sin pi/320 x
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OpenStudy (welshfella):
yea
OpenStudy (kimberly_pr):
YAY, thanks :)
Can you guys help me with another question? :/
OpenStudy (kimberly_pr):
I will be back in 20 minutes and will tag you in my question. THANKS! :)
OpenStudy (agent0smith):
I'll be gone by then, there's a fancy lunch that requires my eating skills
OpenStudy (welshfella):
luck for some!! lol!
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OpenStudy (agent0smith):
Yep it's an open bar too :D